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prisoha [69]
3 years ago
10

PlZZZ help picture attached

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
5 0
1/2 / 1/6= 1/2*6=3
The answer is three
larisa86 [58]3 years ago
4 0
1/2 divided by 1/6 is 3 or 3/1 
you  have to divide 2 to 6 and u get 3 
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A certain company makes three grades (A, B, and C) of a particular electrical component. Historically, grade A components have a
IrinaK [193]

Answer:

following are the solution to this question:

Step-by-step explanation:

In part (a):

Phase 1: Identifies a reasonable confidence period with both the title or form and checks suitable conditions. one z-interval test, p, that true percentage of defective parts in such a lot of Clauses:

1. Unique component sampling

2. This survey size is enough, to the fact to conclude the composition of that percentage of a sample was roughly natural, which the amount for successes and the number of losses are either greater than 10 (or 5 or 15). Needs to check: A 200-component representative selection of a big batch was picked. Each has far more than 15 achievements or failures (16 and 184).

Phase 2: Mechanisms Correct Pick problems for Pink and Blue it Committee of a College. Similar products are part of the program of a College Board. It is prohibited for such resources to be used and distributed online or in a printed form far beyond the participation of the college in the package, which leads to intervals (0.0424, 0.1176).

Phase 3: Background analysis In just this study, we consider 95% of its computed value to have between 4.24% and 11.76% for both the real number of defective components within the batch.

In part (b):

Its standard deviation of 95 percent found in Part (a) allows a company to eliminate class A as its 2 percent faulty rate is not among the computed value within this interval. It period however does not enable the company to decide between levels B and C, since the two faulty rates (5% and 10%) were examined.

Scoring: In 4 components the question is rated. Section 1 comprises part (a) step 1; part (a) or step 2 comprises of the part (a), part (3), part (a), and part (4) (b). The part was marked as correct (E), partly right (P) (I).

4 0
2 years ago
It is a solid shape that contains lateral surface and two circular bases which are parallel and congruent.
ad-work [718]

Answer:

B (cylinder)

Step-by-step explanation:

Two <u>circular</u> bases which are parallel and congruent :

This basically means that the shape contains a circular base (supposedly the bottom), but since it has two bases, its on the top and the bottom. Because it's congruent, the bases are both equal in shape and size. It is also parallel as well, in which the bases have the same distance between them.

The cube doesn't have any circular bases.

The sphere doesn't have any faces, nor edges.

A cone has a circular base, but it doesn't have two.

A cylinder has two circular bases, as well as they are parallel and congruent.

So, your answer is B (cylinder).

Hope this helped !

8 0
2 years ago
Please answer number one as well as show your work thank you!
sveta [45]

√2 is irrational

a rational number Q can be expressed in the form \frac{a}{b} where a and b are integers.

- 18 = \frac{- 18}{1} ⇒ rational

\frac{2}{3} ⇒ rational

3.14 = \frac{314}{100} ⇒ rational

√2 = 1.414213562...... ⇒ irrational


8 0
2 years ago
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
2 years ago
Captain has $30 flame has a $20 note $5 notes . how much more moneny does captain have
SCORPION-xisa [38]

Captain has $30 money

Flame has $20 +$5 =$25

difference =30-25=5

Captain has $5 more money

5 0
2 years ago
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