The percentage of tardiness among the 102 pupils is 2.94.
<h2>Calculation of the percentage</h2>
According to the query,
Course A: Total number of students = 102
Number of tardy students = 3
Percent of students tardy in course A = (number of tardy students/total
number of students) * 100
=(3/102)*100
= 2.941
≈2.94
In case of course B: Total number of students = 85 & tardy student = 5
So, the percent of tardy student = (5/85)*100 = 5.88 %
Therefore, it is concluded that the percentage of student tardiness in course A is 2.94.
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9514 1404 393
Answer:
-1 < x < 2
Step-by-step explanation:
The graph indicates the variable may take on values between -1 and 2, not including those values. The compound inequality is written ...
-1 < x < 2
Answer:
where are the graphs
Step-by-step explanation:
you can upload files to brainly to help the community understand the question. besides, without looking it's probably a curve and a line
Answer:
22,950
Step-by-step explanation:
subtract 51,550 and 28,600. 0 - 0 = 0 then 5-0=5 5-6 you can not do so you barrow from the 1. 1 becomes 0 and 5 becomes 15. 15-6=9. 0-8 you can not do so you need to borrow from the 5. 5 becomes 4 and 0 becomes 10. 10-8=2. Finally, 4-2=2. Put is all together and you have 22,950.
Answer:
Selling Price = M.P. – Discount = 100 – 5 = Rs. 95. If S.P. is Rs 95, then M.P. is Rs. 100.
