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3 years ago

Can someone please help with this! I will mark brainliest to the best answer!!

Mathematics

1 answer:

Citrus2011 [14]3 years ago

5 0

Answer:

neither

Step-by-step explanation:

Its not a causation

In this scenario saying that the number of ice creams sold and shark attacks would be negative causation and that makes no sense.

There isnt an association either I dont think

They dont directly link

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Please help I’ll mark brainlist

Kay [80]

Answer:

⚪ 4: three right triangles and one acute-angled triangle.

Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

A tennis match requires that a player win three of five sets to win the match. If a player wins the first two sets, what is the

Pavlova-9 [17]

Using it's concept, it is found that there is a 0.875 = 87.5% probability that the player wins the match.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, these following outcomes result in the player winning the match:

Wins the third set, with 0.5 probability.

Loses the third set but wins the fourth, each with 0.5 probability.

Loses the third and fourth sets but wins the fifth, each with 0.5 probability.

Hence, the probability that he wins the match is given as follows:

p = 0.5 + 0.5² + 0.5³ = 0.875.

More can be learned about probabilities at brainly.com/question/14398287

5 0

2 years ago

A function $f$ has a horizontal asymptote of $y = -4,$ a vertical asymptote of $x = 3,$ and an $x$-intercept at $(1,0).$ Part (a

Masja [62]

1. $f$ has a horizontal asymptote at $y=-4$

This means that

$\displaystyle\lim_{x\to\pm\infty}f(x)-(-4)=0$

(for at least one of these limits)

2. $f$ has a vertical asymptote at $x=3$

This means that $f$ has a non-removable discontinuity at $x=3$ . Since $f$ is some rational function, there must be a factor of $x-3$ in its denominator.

3. $f$ has an $x$ -intercept at (1, 0)

This means $f(1)=0$ .

(a) With

$f(x)=\dfrac{ax+b}{x+c}$

the second point above suggests $c=-3$ . The first point tells us that

$\displaystyle\lim_{x\to\pm\infty}\frac{ax+b}{x-3}+4=0=\lim_{x\to\pm\infty}\frac{ax+b+4x-3}{x-3}=0$

In order for the limit to be 0, the denominator's degree should exceed the numerator's degree; the only way for this to happen is if $a=-4$ so that the linear terms vanish.