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soldi70 [24.7K]
3 years ago
6

PLEASE HELP!!! use the pic to understand the question

Mathematics
1 answer:
AURORKA [14]3 years ago
6 0

Answer:

this is confusing. I'll try my best to sort it out for you. I'll tap in once I figure it out

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Step-by-step explanation:

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(HURRY! I'M BEING TIMED)Write the partial fraction decomposition of the rational expression.
Aleonysh [2.5K]

Answer:

The partial fraction decomposition is \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}.

Step-by-step explanation:

Partial-fraction decomposition is the process of starting with the simplified answer and taking it back apart, of "decomposing" the final expression into its initial polynomial fractions.

To find the partial fraction decomposition of \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}:

First, the form of the partial fraction decomposition is

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{A}{x + 1}+\frac{B}{\left(x + 1\right)^{2}}+\frac{C}{x + 2}

Write the right-hand side as a single fraction:

                             \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B}{\left(x + 1\right)^{2} \left(x + 2\right)}

The denominators are equal, so we require the equality of the numerators:

             - 4 x^{2} + 13 x - 12=\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B

Expand the right-hand side:

           - 4 x^{2} + 13 x - 12=x^{2} A + x^{2} C + 3 x A + x B + 2 x C + 2 A + 2 B + C

The coefficients near the like terms should be equal, so the following system is obtained:

\begin{cases} A + C = -4\\3 A + B + 2 C = 13\\2 A + 2 B + C = -12 \end{cases}

Solving this system, we get that A=50, B=-29, C=-54.

Therefore,

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}

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3 years ago
The absolute value of a number is its _____ from 0.
Lena [83]

The absolute value of a number is its distance from 0.


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3 years ago
a sticker cost15 cent and a packet of 8 similar stickers cost 1 dollar. clementbuys 37 stickers. what is the least amount of mon
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I think 5 packs of the 8 costs $5.00 
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9(x +1) +{2y(z -1)}/2<br> Solve for y<br><br> How do you do this? I’m confused
Nezavi [6.7K]
Answer
If only {2y(z-1)} is being divided by two:

9x+9+yz-y

If whole equation is divided by two:

9x+9+2yz-2y over 2

Explanation: In the first instance, you can cancel out the 2 in the numerator and denominator, which leaves you 9(x+1) + {y(z-1)}. You can then simplify to get 9x+9+yz-y

In the second instance, you distribute 9 to what is inside the parentheses, and get 9x+1. You then distribute 2y to what is inside the parentheses within the brackets and get 2yz-2y. You are then left with 9x+9+2yz-2y over 2

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3 years ago
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