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Advocard [28]
4 years ago
13

Find the equation for the line passing through the point (3,−4) ( 3 , − 4 ) and parallel to the line whose equation is y=5

Mathematics
1 answer:
Art [367]4 years ago
3 0
Y=5 is a horizontal line parallel the the x axis. the equation of the line passing through the point (3,-4) AND parallel to y=5 is y=-4
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What does 28+87÷3⋅2^3 equal
11111nata11111 [884]

Answer:

260

Step-by-step explanation:

28+29(23)

=28+(29)(8)

=28+232

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3 years ago
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If you know the volume of a cylinder and that a cone has the same base and height of a cone, how would you determine the volume
ratelena [41]

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Multiply the cone's volume by 3

Step-by-step explanation:

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3 years ago
The quadratic formula gives which roots for the equation 2x^2 + x - 6 = 0?
Jet001 [13]

Answer:

The roots are x = (\frac{3}{2}, -2), which is given by option C.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question, we have that:

2x^2 + x - 6 = 0

Which is a quadratic equation with a = 2, b = 1, c = -6. So

\Delta = 1^{2} - 4*2(-6) = 1 + 48 = 49

x_{1} = \frac{-1 + \sqrt{49}}{2*2} = \frac{6}{4} = \frac{3}{2}

x_{2} = \frac{-1 - \sqrt{49}}{2*2} = \frac{-8}{4} = -2

So the roots are x = (\frac{3}{2}, -2), which is given by option C.

3 0
3 years ago
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SashulF [63]

3/100 = 0.03

9000 * 0.03 = 270

She got $270 in commission last month.

8 0
3 years ago
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