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AleksandrR [38]
3 years ago
13

How to find the area of a circle that has a 66 degree angle and a radian of 10

Mathematics
1 answer:
DedPeter [7]3 years ago
7 0
Check the picture below.

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Choose the answer.
myrzilka [38]
**4/5** is equal to .8, so 4/5 is the answer. to check, multiply .8 x 5 = 4
4 0
3 years ago
Read 2 more answers
HELP PLEASE
ankoles [38]

Answer:

1. certain

2.15/31

3.40%

4.unlikely

8 0
3 years ago
What is the value of x?<br> Please show the steps
nordsb [41]
Let D be the endpoint of the angle bisector opposite A on lying on side BC. The angle bisector theorem states that the ratio of BD to CD is equal to the ratio of AB to AC. In this case, you have

\dfrac{2x-1}{3x}=\dfrac9{15}

(This is the same equation that you have, it's just rearranged.)

Multiply both sides by 3x and 15.

15\times3x\times\dfrac{2x-1}{3x}=15\times3x\times\dfrac9{15}
15(2x-1)=3x\times9

Now you can solve for x.

30x-15=27x
3x=15
x=5
6 0
3 years ago
For the Black Panther Trip 420 students were scheduled to go. After collecting more parent surveys, 15% more students are going
natulia [17]

Answer: $ 10,988.25

Step-by-step explanation:

Hi, to answer this question, first we have to multiply the original number of students scheduled to go to the trip (420) by the added students’ percentage (15%) in decimal form (divided by 100)

420 x (15/100) = 420 x 0.15 = 63 students added

Adding the number of extra students to the original number:

420+63 = 483 students (total number of students)

Finally, we have to multiply the result by the cost of each admission ticket (22.75)

483 x 22.75 = $ 10,988.25  

4 0
3 years ago
Identify the hyperbolas (represented by equations) whose centers are at (2, 1)
weqwewe [10]
When the transverse axis is horizontal, a hyperbola centered at (h,k) has formula (x-h)^2/a^2-(y-k)^2/b^2=1. Plug in h=2, k=1, the formula is (x-2)^2/a^2-(y-1)^2/b^2=1 for some a,b. If the transverse axis is vertical, the formula is (y-h)^2/a^2-(x-k)^2/b^2=1, and (y-2)^2/a^2-(x-1)^2/b^2=1 in our case.
5 0
3 years ago
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