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Yuri [45]
3 years ago
13

Which factor in 5.32 x 10^9 shows a power of 10? 1. 10^9 2. 9 3. 10 4. 5.32

Mathematics
1 answer:
Elden [556K]3 years ago
3 0

Option 3 is correct. The factor in 5.32 x 10^9 that shows the power of 10 is 10

Given the scientific notation 5.32 x 10^9

The given power of 10 in the expression is 9.

In order to know the factor in the function that gives the power of 10, <em>we will write the expression to the power of 10 as shown;</em>

= 5.32 \times 10^9 \\= 0.532 \times 10^1 \times 10^9  \\= 0.532 \times 10^{1+9}\\=0.532 \times 10^{10}

Hence the factor in 5.32 x 10^9 that shows the power of 10 is 10

Learn more here: brainly.com/question/10401258

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\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ X(\stackrel{x_1}{-6}~,~\stackrel{y_1}{2})\qquad Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ XZ=\sqrt{[5-(-6)]^2+[8-2]^2}\implies XZ=\sqrt{(5+6)^2+(8-2)^2} \\\\\\ XZ=\sqrt{121+36}\implies \boxed{XZ=\sqrt{157}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad Y(\stackrel{x_2}{8}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ ZY=\sqrt{(8-5)^2+(2-8)^2}\implies ZY=\sqrt{9+36}\implies \boxed{ZY=\sqrt{45}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{perimeter}{14+\sqrt{157}+\sqrt{45}}\qquad \approx \qquad 33.2

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