All categories

3 years ago

HELP ME!! SOMEBODY PLEASE HELP ME

Mathematics

1 answer:

IRISSAK [1]3 years ago

4 0

6^2 = x (x - 9)
x^2 - 9x - 36 = 0
(x -12)(x + 3) = 0
x - 12 = 0; x = 12
x +3 = 0; x = -3

so in this case x = 12 then DC = 12 - 9 = 3

y^2 = 12^2 - 6^2
y^2 = 144 - 36
y^2 = 108
y = 10.4

You might be interested in

Please help i have no idea how to answer this

BabaBlast [244]

Answer: 1/32
Multiple 1/4 x 1/8 to get your answer

4 0

2 years ago

Read 2 more answers

The total amount of money, M, that Bob earns each week at his job is proportional to the wages, w, that he earns per hour for wo

Svetach [21]

M α W

M = c1 * W

W α T

W = c2 * T

M = c3 * T

I think your question is missing ?

4 0

3 years ago

Read 2 more answers

The police department uses a formula to determine the

laiz [17]

9514 1404 393

Answer:

78.71 mph

Step-by-step explanation:

You're looking for the solution to ...

d = 88

0.0015r^2 +r = 88

0.0015r^2 +r -88 = 0

Using the quadratic formula*, we find ...

r = (-1 +√(1² -4(0.0015)(-88)))/(2×0.0015)

r = (-1 +√1.528)/0.003 = 0.236123/0.003 = 78.7077

The speed of the car was about 78.71 mph.

_____

* The quadratic formula will also give a negative answer of about -745 mph, which is not relevant to the situation.

8 0

2 years ago

(ab^2 x -b^4a^3)^2<br><br> What is the answers

Umnica [9.8K]

Answer:

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

Step-by-step explanation:

Given the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

solving the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

$\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2$

$a=ab^2x,\:\:b=b^4a^3$

so the expression becomes

$=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2$

$=a^2b^4x^2-2a^4b^6x+a^6b^8$

Thus,

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

3 0

2 years ago

A tent forms an equilateral triangular prism, with both triangular faces exposed. each side of the triangular face has a length

Soloha48 [4]

Given:
Equilateral Triangular Prism
Each side of the triangular face has a length of 196cm
The tent is 250cm long

I have attached an image of the tent. Since the height of the tent is also the height of the triangle, I will solve for the height of the triangle using Pythagorean theorem.

I divided the equilateral triangle into 2 right triangle. The height then becomes the long leg of the triangle. The hypotenuse is 196cm and the short leg is 98cm, half of one side of the triangle.

a² + b² = c²
a² = c² - b²
a² = (196cm)² - (98cm)²
a² = 38,416cm² - 9,604cm²
a² = 28,812cm²
a = √28,812cm²
a = 169.74cm

The height of the tent is 169.74 centimeters.

6 0

3 years ago