<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Cgeq%20-%5Cfrac%7B1%7D%7B6%7D%20-%5Cfrac%7B2%7D%7B9%7D%20x" id="TexF

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2 years ago

ormula1" title="\frac{1}{2} \geq -\frac{1}{6} -\frac{2}{9} x" alt="\frac{1}{2} \geq -\frac{1}{6} -\frac{2}{9} x" align="absmiddle" class="latex-formula">
can someone explain how to do this i dont get fractions

Mathematics

2 answers:

Evgesh-ka [11]2 years ago

7 0

They are saying that 1/6 - 2/9x is greater than 1/2

1/2=50%
1/6= 16.6%
2/9x=18%

16%-18% is not greater so therefore this answer is false

vodomira [7]2 years ago

4 0

Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
x
≥
−
3
x
≥
-
3
Interval Notation:
[
−
3
,
∞
)

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The graph below shows the value of Edna's profits f(t), in dollars, after t months:

umka21 [38]

Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), $x=6$ and $x=18$ are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
$x=6$
$x-6=0$
$x=18$
$x-18=0$

$(x-6)(x-18)=x^{2}-6x-18x+108$
$=x^{2}-24x+108$

Now that we have our quadratic function, we are going to use the average formula: $m= \frac{f(9)-f(3)}{9-3}$
$where$
$f(9)$ is the function evaluated at the 9th month
 $f(3)$ is the function evaluated at the 3rd month

$m= \frac{f(9)-f(3)}{9-3}$
$m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}$
$m= \frac{-27-45}{6}$
$m= \frac{-72}{6}$
$m=-12$

We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: B. −11.63 dollars per month.