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krek1111 [17]
3 years ago
11

ormula1" title="\frac{1}{2} \geq -\frac{1}{6} -\frac{2}{9} x" alt="\frac{1}{2} \geq -\frac{1}{6} -\frac{2}{9} x" align="absmiddle" class="latex-formula">
can someone explain how to do this i dont get fractions
Mathematics
2 answers:
Evgesh-ka [11]3 years ago
7 0
They are saying that 1/6 - 2/9x is greater than 1/2


1/2=50%
1/6= 16.6%
2/9x=18%

16%-18% is not greater so therefore this answer is false

vodomira [7]3 years ago
4 0
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
x
≥
−
3
x
≥
-
3
Interval Notation:
[
−
3
,
∞
)
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A cone has a height of 8 inches in diameter of 6.4 inches what is the volume of the cone?
maxonik [38]
The volume of the cone is 85.79 since the radius is 3.2
5 0
3 years ago
Anyone know this ???
sineoko [7]
Make into improper fraction

5 and 1/6=5+1/6=30/6+1/6=31/6

3 and 2/4=3+2/4=3+1/2=6/2+1/2=7/2

5 and 1/6 times 2 and 2/4=
31/6 times 7/2=
217/12=
216/12+1/12=
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8 0
3 years ago
Find the difference: 11 - 4.7
shutvik [7]

<u><em>Answer: 6.3 *The answer must be have a decimal point.*</em></u>

Explanation:

First, subtract by the numbers. Subtract it's going to be find the difference between the numbers.

11-4.7=6.3

You can also add by the numbers.

6.3+4.7=11

11-6.3=4.7

Hope this helps!

Thank you!

Have a great day!

7 0
3 years ago
Read 2 more answers
What is the slope of PV?
vagabundo [1.1K]
Not sure but It should be -4/1
5 0
2 years ago
Ya idk how to do this plz help explain if you can
Svet_ta [14]

Answer:

  92 attendees had activity cards

Step-by-step explanation:

Let x be the number of students with activity cards. Then 130-x is the number without, and the total revenue is ...

  7x +10(130 -x) = 1024

  7x +1300 -10x = 1024 . . . . eliminate parentheses

  -3x = -276 . . . . . . . . . . . . . collect terms; subtract 1300

  x = 92 . . . . . . divide by 3

92 students with activity cards attended the dance.

_____

<em>Comment on the solution</em>

Often, you will see such a problem solved using two equations. For example, they might be ...

Let 'a' represent the number with an activity card; 'w' the number without. Then ...

  • a+w = 130 . . . . the total number of students
  • 7a +10w = 1024 . . . . the revenue from ticket sales

The problem statement asks for the value of 'a', so you want to eliminate w from these equations. You can do that using substitution. Using the first equation to write an expression for w, you have ...

  w = 130-a

and making the substitution into the second equation gives ...

  7a +10(130 -a) = 1024

This should look a lot like the equation we used above. There, we skipped the extra variable and went straight to the single equation we needed to solve.

5 0
3 years ago
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