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Nezavi [6.7K]
3 years ago
13

Which expressions are equivalent to the one below ? check all that apply :)

Mathematics
2 answers:
lys-0071 [83]3 years ago
8 0

Answer:

its b and e

Step-by-step explanation:

Stella [2.4K]3 years ago
5 0

Answer:

Option D and E are  equivalent to the given expression.

Step-by-step explanation:

Given : \frac{21^x}{3^x}

Solution:

\frac{21^x}{3^x}

Using identity : \frac{a^x}{b^x} = (\frac{a}{b})^x

(\frac{21}{3})^x   -- Option E

Now this can be written as  21^x = 7^x \times 3^x

Identity : a^x \times b^x = (a \cdot b)^x

\frac{7^x \times 3^x}{3^x}  -- Option D

(7)^x   -- Option D

Thus Option D and E are  equivalent to the given expression.

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What is the length of the diagonal of the rectangular solid shown? please help!!!!
Olin [163]

Answer:

D. diagonal = 20.10 cm

Step-by-step explanation:

Find the bottom diagonal using the length and width.

diagonal² = 8² + 12²

diagonal = √64+144

diagonal = √208

diagonal = 4√13

---------------------------------------------------------------------------------------------------------

Find diagonal of the rectangular solid:

diagonal² = (4√13)² + 14²

diagonal² = 208 + 196

diagonal = √404

diagonal = 20.10 cm

7 0
2 years ago
Solve for u:−14u+32=−6.
zubka84 [21]

Answer:u=19/7 or 2.714286 or 2 5/7

Step-by-step explanation:

−14u+32=−6

Step 1: Subtract 32 from both sides.

-14u+32-32=-6-32

-14u=-38

Step 2: Divide both sides by -14.

-14u/-14=-38/-14

U=19/7

3 0
3 years ago
Check out the photo for the question
Anestetic [448]

Answer:

50

Step-by-step explanation:

42/n³∑k²+12/n²∑k+30/n∑1

=42/n³[n(n+1)(2n+1)/6]+12/n²[n(n+1)/2]+30/n [n]

=7n(n+1)(2n+1)/n³+6n(n+1)/n²+30

=7(n+1)(2n+1)/n²+6(n+1)/n+30

=[7(2n²+3n+1)+6(n²+n)+30n²]/n²

=[14n²+21n+7+6n²+6n+30n²]/n²

=[50n²+27n+7]/n²

=[50+27/n+7/n²]

→50 as n→∞

because 1/n,1/n²→0 as n→∞

4 0
3 years ago
Read 2 more answers
What is the point slope equation of the line with slope 5 that passes through (2,-3)
blsea [12.9K]

Answer:12

Step-by-step explanation:

7 0
3 years ago
15x—3y=12<br> Y=5x—4<br><br> 4x—y=-4<br> -8x+2y=2
fredd [130]
15x-3y=12
<u>y=5x—4
</u>I'm also not sure what your question is, but this is what I got by solving it like a regular equation.

15x-3(5x-4)=12
15x-15x+12=12
0=12-12
0=0

4x-y=-4
<span><u>-8x+2y=2</u>
</span>
-y=-4-4x /: (-1)
y=4+4x

-8x+2y=2
-8x+2(4+4x)=2
-8x+8+8x=2
0=-6
6 0
3 years ago
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