A: Universe (It surrounds everything) B: Galaxy (Smaller than the universe but larger than the rest) C: Solar System D: Mars
Cant help you for number 2 though. Hope this helps :)

8 0

3 years ago

Read 2 more answers

Four friends split equally a lunch bill of 36.96 plus 20% tip. How much did each person pay

castortr0y [4]

Let P = how much each person paid.

P = [(36.96)(0.20) + 36.96]/4

Solve for P to find your answer.

8 0

2 years ago

Bob thought of an even and odd number, multiplies the numbers together, added 6, divided by 5, and subtracted 3 to give an answe

Marina CMI [18]

Answer:

Step-by-step explanation:

Working backward, we can find Bob's initial product.

We subtracted 3 to get 1, so we had 4.

We divided by 5 to get 4, so we had 20.

We added 6 to get 20, so we had 14

After Bob multiplied the two numbers together, he had 14. We know that 14 is the product of 2 and 7. The odd number is 7.

7 0

3 years ago

The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

2 years ago