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polet [3.4K]
3 years ago
5

What equation best models this data? (Use y to represent the population in millions, and t to represent the year, assuming that

2010 is t = 0.)

Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0

Answer:

y = 2.31x + 309.35

Step-by-step explanation:

Whenever you are checking for a best fitting equation you want to check if it has a constant slope.  If it does then the relation is linear and super easy.

So, since the t values are increasing by the same amount you want to see if the y values are  too.  And they are, each population entry is increasing by 2.31, this is the slope.  

Also, keep in mind you can caluclate slope with the equation \frac{y_2-y_1}{x_2-x_1}  here x is replaced by t though.

Now, since we know it's linear and we know the slope we can find the equation with the formula  y - y1 = m(x - x1) where again, x is replaced by t and m is the slope 2.31

I am just going to use the first point.  so x1 = t1 = 0

y - 309.35 = 2.31(x-0)

y = 2.31x + 309.35

Let me know if there was something you didn't understand.  

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The bad debt ratio for a financial institution is defined to be the dollar values of loans defaulted divided by the total dollar
Nimfa-mama [501]

Answer:

(a) NULL HYPOTHESIS, H_0 : \mu \leq  3.5%

    ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5%

(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Step-by-step explanation:

We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.

We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

(a) Let, NULL HYPOTHESIS, H_0 : \mu \leq  3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}

ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}

The test statistics that will be used here is One-sample t-test;

                T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where,  \bar X = sample mean debt ratio of Ohio banks = 6%

             s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} } = 1.83%

             n = sample of banks = 7

So, test statistics = \frac{6-3.5}{\frac{1.83}{\sqrt{7} } }  ~ t_6

                             = 3.614

(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Hence, Federal banking officials claim was correct.

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Subtract the deductible from the total:

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Takashi then needs to pay 20% of what is left.

200 x 0.20 = 40

Takashi has to pay the 150 deductible plus 40 for a total of $190

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Answer:

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Step-by-step explanation:

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3 years ago
Find the area of the regular polygon.<br>Round to the nearest tenth.<br>16 ft​
Sladkaya [172]

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Given that the side of the regular polygon is 16 feet.

We need to determine the area of the polygon.

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Area =\frac{s^2 n}{4 \ tan \frac{180}{n}}

where n is the number of sides,

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Dividing, we get;

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Rounding off to the nearest tenth, we have;

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Answer:

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Step-by-step explanation:

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This has zeros that can be found by the usual methods of solving quadratics:

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The positive value of x corresponds to what I might call an "apex." (See the first attachment.) The negative value is where the function turns around an approaches the horizontal asymptote from below. (See the second attachment.)

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