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Georgia [21]
3 years ago
5

A. A container holds 0.500 qt of liquid. How many milliliters of lemonade will it hold?

Mathematics
1 answer:
Nady [450]3 years ago
8 0

Answer:

<em>A container can hold 473.176 ml</em>

<em>42.52 grams is nitrogen. </em>

Step-by-step explanation:

<u>Part A:</u>

We have given that a container holds 0.500 qt . Now we have to find how many milliliters of lemonade it can hold.

We know that 1 qt = 946.353 ml

To find how many milliliters of lemonade a container hold, we have to convert 0.500qt into ml.

As we have mentioned above that 1 qt = 946.353 ml

Multiply the volume value by 946.353 .

0.500 * 946.353

= 473.176 ml

<em>It means a container can hold 473.176 ml</em>

<u>Part B:</u>

Convert the unit oz  to grams. The ratio is 1 ounce is to 28.34 grams.

We have 10.0 oz.

10* 28.34 = 283.495

This would mean 10 oz is equivalent to 283.50 grams. It is given that the fertilizer is 15% by mass nitrogen. It means for every 100 g of fertilizer 15 grams of that is nitrogen. Hence for every 283.50 grams of fertilizer

<em>283.50 * (15/100) = 42.52 grams is nitrogen. </em>

<em></em>

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Answer:

The amount invested in the mutual fund that earned 5% was $1,000

The amount invested in the mutual fund that earned 3% was $1,800

Step-by-step explanation:

Let

x ----> the amount invested in the mutual fund that earned 5%

y ----> the amount invested in the mutual fund that earned 3%

we know that

x+y=2,800 ----> y=2,800-x ----> equation A

5\%=5/100=0.05

3\%=3/100=0.03

0.05x+0.03y=104 ----> equation B

Solve the system by substitution

substitute equation A in equation B

0.05x+0.03(2,800-x)=104

Solve for x

0.05x+84-0.03x=104

0.05x-0.03x=104-84

0.02x=20

x=\$1,000

<em>Find the value of y</em>

y=2,800-x

y=2,800-1,000=\$1,800

therefore

The amount invested in the mutual fund that earned 5% was $1,000 and the amount invested in the mutual fund that earned 3% was $1,800

5 0
3 years ago
Angle 0 lies in the second quadrant and sin 0 = 3/5 cos= coy =
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Consider the right triangle ABC with legs AB=4, AC=3 and hypotenuse BC=5. Angle B has
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Since O lies in second quadrant \cos O\ \textless \ 0 and 
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Answer:

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Step-by-step explanation:

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Find the compound amount for the deposit. (Round to two decimal places).
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Answer:

Step-by-step explanation:

Problem

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