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3 years ago

Help urgent, which functions are bounded below but not above? Choose all answers that apply.

Mathematics

1 answer:

evablogger [386]3 years ago

3 0

Answer:

c, e, f, and i

Step-by-step explanation:

a. is bounded above at y = 1 and below at y = 0

b. is unbounded both above and below

c. is bounded below at y = 0 and unbounded above

d. is unbounded both above and below

e. is bounded below at y = 0 and unbounded above

f. is bounded below at y = 0 and unbounded above

g. is bounded below at y = 0 and bounded above at y = 1

h. is unbounded both above and below

i. is bounded below at y = 0 and unbounded above

j. is unbounded both above and below

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VladimirAG [237]

Answer:

The answer to your question is h = 125.85 ft = 126 ft

Step-by-step explanation:

Process

1.- Determine two equations to solve the problem

$tan 14 = \frac{h}{x}$ (1)

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from (1) h = xtan14

substitute in (2) tan 47 = $\frac{xtan14}{x - 386}$

solve for x tan47(x - 386) = xtan14

1.07x - 413.9 = 0.25x

1.07x - 0.25x = 413.9

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x = 413.9/0.82

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4 years ago

If the domain (or pre-image) is (-4, -2), (5, 9), (-6, 2) and the range (or image) is

Neko [114]

Answer: 90 degrees clockwise

This is equivalent to 270 degrees counterclockwise

The rule for either rotation is $(x,y) \to (y,-x)$

The x and y coordinates swap places, and the new second coordinate flips from positive to negative (or vice versa).

The diagram below shows an example of this for the point (-4,-2) rotating to (-2, 4). The center of the rotation is the origin (0,0).

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2 years ago

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fiasKO [112]

Answer:

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Step-by-step explanation:

you should set up your problem like this:

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2 years ago

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baherus [9]

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Answer:

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Step-by-step explanation:

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