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solong [7]
3 years ago
7

Help urgent, which functions are bounded below but not above? Choose all answers that apply.

Mathematics
1 answer:
evablogger [386]3 years ago
3 0

Answer:

c, e, f, and i

Step-by-step explanation:

a. is bounded above at y = 1 and below at y = 0

b. is unbounded both above and below

c. is bounded below at y = 0 and unbounded above

d. is unbounded both above and below

e. is bounded below at y = 0 and unbounded above

f. is bounded below at y = 0 and unbounded above

g. is bounded below at y = 0 and bounded above at y = 1

h. is unbounded both above and below

i. is bounded below at y = 0 and unbounded above

j. is unbounded both above and below

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Morgarella [4.7K]

Answer:

a. Compressed f toward the x-axis, and then translated it left 4 units.

Step-by-step explanation:

General equation for this is:

 y = a√(x - h) + k

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  • h is how much it's shifted in the x-direction
  • k is how much it's being shifted in the y-direction

We're given:

g(x) = 1/2√(x + 4)

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My a-value is 1/2, so the original function f(x) is being compressed by 1/2 toward the x-axis.

My h value is -4 so it's being shifted by 4 units. It's shifted to the left because it's negative.

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3 years ago
What expressions are equivalent to 5x + (x+6) + 3x
anyanavicka [17]

Answer:

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Step-by-step explanation:

<u>Step 1:  Distribute</u>

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<u>Step 2:  Combine like terms</u>

5x + x + 6 + 3x

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Answer: 9x + 6

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