All categories

3 years ago

Calculate surface area of pyramids

Mathematics

1 answer:

joja [24]3 years ago

3 0

A=138.53 in
Use the formula and replace the variables with the length, width, and height to get the answer

You might be interested in

Helppp pleaseee this is due on 10 minutes with explanation pleasee thank you

Nat2105 [25]

Answer:

Jed's Market

Step-by-step explanation:

Find out the cost of one candy bar for each store:

Smith's:

9.00 ÷ 3 = $3.00

Green's:

10.00 ÷ 4 = $2.50

Jed's:

12.00 ÷ 5 = $2.40

Wan's:

It already tells you the price for each: $2.75

Finding the best deal:

Look at all our costs per 1 candy bar. Which one has the smallest price?
Because $2.40 is the smallest price, Jed's Market has the best buy.

I hope this helps!

8 0

3 years ago

Peyton needed to get her computer fixed. She took it to the repair store. The

Lelu [443]

Answer:

The cost of labor per hour is $105.

The expression is 4x + 77 = 497

Step-by-step explanation:

The expression is 4x + 77 = 497, where 4x represents the cost of labor per hour, 77 is the cost of the parts, and 497 is the total.

4x + 77 = 497

4x + 77 - 77 = 497 -77

4x = 420

4x/4=420/4

x = 105

5 0

3 years ago

URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

3 years ago

If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the

Gnesinka [82]

Answer:

Step-by-step explanation:

If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18,

x=(m+9)/2

y=(2m+15)/2

z=(3m+18)/2

the average of x, y, and z

=(x+y+z)/3

=(m+9+2m+15+3m+18)/3

=(6m+42)/3

=2m+14

ans is C

8 0

3 years ago

Read 2 more answers

What is 4 6/8+11 1/3

aivan3 [116]

So 4 6/8= (32/4)+6/8=38/8
11 1/3=(33/3)+1/3=34/3
so 38/8+(34/3)

to add you must get the bottom number equall so

114/24+272/24=386/24=16 1/12

6 0

4 years ago

Read 2 more answers