Answer: 0.87 g of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel.
Explanation:
According to the dilution law,
where,
= concentration of ist progesterone gel = 8%w/w
= weight of ist progesterone gel = x g
= concentration of another progesterone gel = 4% w/w
= weight of another progesterone gel = 1.45 g
= concentration of resulting progesterone gel = 5.5%w/w
= weight of resulting progesterone gel = (x+1.45) g
Thus 0.87 g of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel.
The answer is D! This is because there is a change the colour, a change in odor and a precipitate formed!
Answer:
A strong base, such as NaOH. The amount of OH added shouldn't exceed 0.35 mols (though i would stop at 0.30 mols)
Explanation:
a weakly basic salt can be turned into a buffer by the addition of a strong base, and a weakly acidic salt can be turned into a buffer with a strong acid
The fact that they lay like 300 eggs. And maybe that they are fast.
<span>Answer:
Moles C10H16O = 24.6 g/ 153.23 g/mol = 0.161
Moles benzene = 98.5 g / 78.1121 g/mol = 1.26
Mole fraction benzene = 1.26 / 1.26 + 0.161 = 0.887
vapor pressure = 100 x 0.887 = 88.7 mm Hg</span>
