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3 years ago

Which of the following compounds are ionic?

Chemistry

1 answer:

julsineya [31]3 years ago

7 0

Answer:

a. KCl, c. BaCl2 and e. LiF.

Explanation:

Hello,

In this case, we can identify the ionic compounds by verifying the difference in the electronegativity between the bonding compounds when it is 1.7 or more (otherwise it is covalent) as shown below:

a. KCl: 3.0-0.9=2.1 -> Ionic.

b. C2H4: 2.5-2.1=0.4 -> Covalent.

c. BaCl2: 3.0-0.8=2.2 -> Ionic.

d. SiCl4: 3.0-1.8=1.2 -> Covalent.

e. LiF: 4.0-1.0=3.0 -> Ionic.

Therefore, ionic compounds are a. KCl, c. BaCl2 and e. LiF.

Regards.

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The density of lithium is 0. 546 g/cm3. what volume is occupied by 3. 66 x 10 23 atoms of lithium?

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The volume occupied by 3.66 x $10^{23}$ atoms of lithium is 7.73 $cm^3$

<h3>What is Density?</h3>

The density of a substance is defined as the mass of the substance per unit volume. It is often denoted by the symbol ρ

The density of a substance is given by,

$\rho = \frac{m}{V}$

The mass of a substance is the measure of the amount of matter present in it. It is generally measured in grams (g) or kilograms (kg).

The volume of a substance is defined as the amount of 3D space occupied by it.

<h3>What is Mole Concept?</h3>

It is a concept which uses mole as a unit to measure the number of atoms, molecules or ions.

A mole is defined as the amount of substance which has the same number of elementary particles as there are atoms in 12 grams of $\ce{^{12}C}$

1 mole = Avogadro's number = 6.022 x $10^{23\\$ atoms

<h3>Steps to find out the volume</h3>

Molar Mass of Lithium = 6.94 g/mol

1 mole of Lithium has 6.022 x $10^{23}$ atoms

3.66 x $10^{23}$ atoms of lithium has molar mass = $\frac{6.94 g}{6.022\times10^{23} } \times 3.66 \times 10^{23}$

$m = 4.218 g$

Substitute in density formula,

$\rho = \frac{m}{V}$

$V = \frac{m}{\rho}$

$=\frac{4.218g}{0.546g/cm^3}$

= 7.73 $cm^3\\$

Therefore, 3.66 x $10^{23}$ atoms of lithium occupies 7.73 $cm^3\\$ of volume.

Learn more about the mole concept:

brainly.com/question/1427235

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