What is the most efficient way to make up a hepes buffer at 8.5? what starting compounds and reagents will you use?
1 answer:
The value of HEPES is 7.5.
Now, to prepare a HEPES buffer at 8.5:
A proper amount of HEPES is mixed with distilled water (sterilised) to avoid any contamination. After that check the pH with the help of pH scale or pH meter.
Now, identify the pH and if pH is higher than 8.5, then a particular amount of hydrochloric acid is added to it drop by drop to get the HEPES buffer at 8.5.
If pH is lower than 8.5, then a specific amount of base such as sodium hydroxide is added to it drop by drop to get HEPES buffer at 8.5.
At last, when 8.5 pH is obtained, the buffer solution is filtered and placed in the container of the glass and then covered by aluminium foil.
You might be interested in
Answer: Option (d) is the correct answer.
Explanation:
Electronegativity value of hydrogen is 2.2.
Electronegativity value of chlorine is 3.16.
Electronegativity value of carbon is 2.55.
Electronegativity value of oxygen is 3.44.
Electronegativity value of nitrogen is 3.04.
Electronegativity value of sodium is 0.93.
Electronegativity value of iodine is 2.66.
Therefore, calculate the electronegativity difference between the bonded atoms as follows.
- Electronegativity difference of HCl = Electronegativity value of chlorine - electronegativity value of hydrogen
= 3.16 - 2.2
= 0.96
- Electronegativity difference of CO = Electronegativity value of oxygen - electronegativity value of carbon
= 3.44 - 2.55
= 0.89
- Electronegativity difference of
= Electronegativity value of nitrogen - electronegativity value of nitrogen
= 3.04 - 3.04
= 0
- Electronegativity difference of NaI = Electronegativity value of iodine - electronegativity value of sodium
= 2.66 - 0.93
= 1.73
So, we can see that highest electronegativity difference is 1.73 and it is shown by NaI molecule.
Thus, we can conclude that a group 1 alkali metal bonded to iodide, such as NaI has the greatest electronegativity difference between the bonded atoms.