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miss Akunina [59]
4 years ago
15

One electron in an atom has the quantum number set (3, 1, 0, ½), and another electron in the same atom has the quantum number se

t (3, 1, 1, ½). they share the
Chemistry
1 answer:
guapka [62]4 years ago
3 0
There are four quantum numbers that describe the placement of electrons in an atom's electron cloud: principal quantum number (n), angular quantum number (l), magnetic quantum number (ml) and electron spin number (ms). When presented, they are written as (n, l, ml, ms).

From the given set, they have same n and l quantum numbers. The n represents the shell, the l as subshell, ml is the orientation in space and ms is the direction of the spin. Therefore, these two electrons of the atom share a subshell but differ in the shape of the orbital only.
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We can still see the shadow of the Earth and/or Earth's surface.
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3 years ago
6) How should the conditions be changed to prevent the volume of a given mass of gas from expanding when its mass is increased
JulijaS [17]

Answer: increase pressure and decrease temperature.

Explanation:

Increasing pressure uses force to make the gas molecules come closer together. (Decreasing pressure allows the molecules to spread out) Decreasing temperature will also cause the molecules of gas to come together closer. (Heat excites molecules causing them to spread out and therefore expand)

6 0
3 years ago
For 100.0 mL of a solution that is 0.040M CH3COOH and 0.010 M CH3COO, what would be the pH after adding 10.0 mL 50.0 mM HCl?
damaskus [11]

Answer:

The pH of the buffer is 3.90

Explanation:

The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:

pH = pKa + log [A-] / [HA]

<em>Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.</em>

<em />

To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:

CH3COO- + HCl → CH3COOH + Cl-

<em>The moles of CH3COO- are its initial moles - the moles of HCl added</em>

<em>And moles of CH3COOH are its initial moles + moles HCl added</em>

<em />

Moles CH3COO-:

Initial moles  = 0.100L * (0.010mol / L) = 0.00100moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.000500 moles

Moles CH3COOH:

Initial moles  = 0.100L * (0.040mol / L) = 0.00400moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.003500 moles

pH is:

pH = 4.75 + log [0.000500] / [0.00350]

<em>pH = 3.90</em>

<em />

<h3>The pH of the buffer is 3.90</h3>
3 0
3 years ago
Consider the following equation. Fe2O3(s) 3H2(g) Right arrow. 2Fe(s) 3H2O(g) Delta. H = 98. 8 kJ, and Delta. S = 141. 5 J/K. Is
mestny [16]

The reaction is spontaneous at high temperatures, and non-spontaneous at low temperatures.

In a thermodynamically closed system, the measure of the non-expansion work by the system and the enthalpy and the entropy is said to be the <u>Gibbs free energy</u>.

<h3>How to determine the Gibbs free energy?</h3>

According to the reaction, the enthalpy change (\rm \Delta H) and the change in the entropy (\rm \Delta S) is positive. The Gibbs free energy is given by, \rm \Delta G = \Delta H - T \Delta S and the reaction will be spontaneous only when the \rm\Delta G is negative.

If there is not much effect on the enthalpy and entropy due to a decrease in temperature, then the value of the Gibbs free energy will be positive and will be close to that of the enthalpy change. In the above reaction enthalpy, change is positive and hence the reaction will be non-spontaneous.

When the temperature is increased then the entropy will affect the overall reaction as the Gibbs free energy will have the opposite sign as that of the entropy. So the reaction will become spontaneous at high temperatures.

Thus, option A is correct.

Learn more about Gibbs free energy here:

brainly.com/question/7988114

4 0
2 years ago
Why is mercury the only metal to have been used in thermometers
levacccp [35]
Most metals are good conductors of heat and they are solids at room temperature. 
5 0
3 years ago
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