1st and 4th options are suitable answers, as these 2 changes are not exactly physical changes as it cant return back to original form and as well as its not cooling, so I feel its 1st and 4th options

7 0

2 years ago

A benzene bonded side group is called?

hammer [34]

It is called a phenyl group

3 0

2 years ago

What is acnsrl spgei

joja [24]

Spring scale
It's a tool used to measure force.

4 0

2 years ago

Consider 4.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.80 L and the temperature is increased to 3

stealth61 [152]

This is an exercise in<u> the General Combined Gas Law</u>.

To start solving this exercise, we obtain the following data:

V₁ = 4.00 l
P₁ = 365 mmHg
T₁ = 20 °C + 273 = 293 K
V₂ = 2,80 l
T₂ = 30 °C + 273 = 303 K
P₂ = ¿?

We apply the following formula:

P₁V₁T₂=P₂V₂T₁ ⇒ General formula

Where:

P₁=Initial pressure
V₁=Initial volume
T₂=end temperature
P₂=end pressure
T₂=end temperature
V₁=Initial temperature

We clear for final pressure (P2)

$\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2}}{V_{2}T_{1}} \ \ \to \ \ \ Formula \end{gathered}$}$

We substitute our data into the formula:

$\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(365 \ mmHg)(4.00 \not{l})(303 \not{K})}{(2.80 \not{l})(293\not{K})} \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{442380 \ mmHg}{ 820.4 } \end{gathered}$}$

$\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=539.224 \ mmHg \end{gathered}$}}$

Answer: The new canister pressure is 539.224 mmHg.

<h2>{ Pisces04 }</h2>

6 0

1 year ago