____________________________________________________
Answer:
Your answer would be a). 2.0 × 10-9
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Work:
In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.
You would use the ph (4.48) to find the ka for "hbro"
[H+]
=
10^-4.48
=
3.31 x 10^-5 M
=
[BrO-]
or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]
Then you would find ka:
(3.31 x 10^-5)^2/0.55 =2 x 10^-9
____________________________________________________
<em>-Julie</em>
The correct option would be that oxygen, nitrogen, and carbon dioxide cannot react with one another.
<h3>Why air components cannot react</h3>
The components of atmospheric air, nitrogen, oxygen, carbon dioxide, etc., cannot react with one another because there is not enough energy in the atmosphere to set the reaction rolling.
For a reaction to take place, there must be enough energy to break the bonds in each air component. This is why the air components will not spontaneously react with one another, except during special events such as lightning and thunder.
More on air components can be found here: brainly.com/question/17288850
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Answer:
619°C
Explanation:
Given data:
Initial volume of gas = 736 mL
Initial temperature = 15.0°C
Final volume of gas = 2.28 L
Final temperature = ?
Solution:
Initial volume of gas = 736 mL (736mL× 1L/1000 mL = 0.736 L)
Initial temperature = 15.0°C (15+273 = 288 K)
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = T₁V₂/V₁
T₂ = 2.28 L × 288 K / 0.736 L
T₂ = 656.6 L.K / 0.736 L
T₂ = 892.2 K
K to °C:
892.2 - 273.15 = 619°C
Answer:
The 2 zeros after the decimal point
The percentage of the water entering the small intestine is absorbed by the small intestine is 92.02%
<h3>Calculation of the percentage:</h3>
Volume of water that is leaving the small intestine should be
= 9400 - 750
=8650 ml
Now the percentage should be
= (8650/ 9400)100
= 92.02 %
Thus 92.02 % of the total water entering the small intestine is absorbed itself by the small intestine.
To know more about small intestine, visit:
brainly.com/question/24180887
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