Answer:
b. You would conclude that the differences in the average scores can be traced to differences in the working memory of the two groups.
Step-by-step explanation:
Though the average scores of the two sets could have lead to various conditions, but retentive ability deminishes with respect to an increase in age. With respect to the age of the elderly people involved, it is expected that some of them would not be able to retain information for a long period of time. Thus, their average score is 72%.
The college students' are younger, so it is expected that they should be able to retain more information. That ability is one of the reasons why their average score is 85%.
It can be concluded from the research that the differences in the average scores is probably due to the working memory of the two groups.
Answer:
1.048
Step-by-step explanation:
<em>
</em>
- <em>
</em> - <em>After</em><em> </em><em>calculati</em><em>ng</em><em> </em><em>the</em><em> </em><em>answer</em><em> is</em><em> </em><em>1</em><em>.</em><em>0</em><em>4</em><em>8</em>
Answer:
c
Step-by-step explanation:
Answer:
Wonka bars=3 and Everlasting Gobstoppers=24
Step-by-step explanation:
let the wonka bars be X
and everlasting gobstoppers be Y
the objective is to
maximize 1.3x+3.2y=P
subject to constraints
natural sugar
4x+2y=60------1
sucrose
x+3y=75---------2
x>0, y>0
solving 1 and 2 simultaneously we have
4x+2y=60----1
x+3y=75------2
multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have
4x+2y=60
4x+12y=300
-0-10y=-240
10y=240
y=240/10
y=24
put y=24 in equation 2 we have'
x+3y=75
x+3(24)=75
x+72=75
x=75-72
x=3
put x=3 and y=24 in the objective function we have
maximize 1.3x+3.2y=P
1.3(3)+3.2(24)=P
3.9+76.8=P
80.7=P
P=$80.9
2860 times .12 equals $343.20
