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bearhunter [10]
3 years ago
6

star wars was showing at the chicago ridge movie theater. there were a total of 36 tickets available for the 7:00 show. Part A I

f 5/6 of the tickets were purchased, how many tickets were bought? Part B 1/5 of the tickets purchased ere by kids aged 17. How many 17 year olds purchased tickets to see star wars.

Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0

Answer:

part a 30

part b 6

Step-by-step explanation:

hope this helps

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Choose the equation that completes the equation. 24 ÷ 6 + 20=
Lynna [10]

Hi Marisa255,

Solution:

First lets solve the given equation:

= 24 / 6 + 20

= 4 + 20

= 24

Now Lets solve A:

= 3(7 + 1)

= (3 x 7) + (3 x 1)

= 21 + 3

= 24

So we see that A and the equation given have the same answers.

Final Answer:

A. 3(7 + 1)

3 0
4 years ago
If a2= 18 and a4= 8, find two possible common ratios. Then, write two sequences lhaving five terms each.
Marizza181 [45]

common ratio = a4/a3 = a3/a2

8/a3 = a3/18

(a3)^2 = 8 * 18

(a3)^2 = 144

a3 = 12 or a3 = -12

common ratio = 8/12 or common ratio = 8/(-12)

common ratio = 2/3 or common ratio = -2/3

Answer: 12 or -12

3 0
3 years ago
Steve earns $0.66 for each unit of work. If he averaged 558
WINSTONCH [101]
52 weeks in a year x 558 units per week x .66 cost of each unit= $19,150.56 a year
3 0
3 years ago
A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

4 0
4 years ago
HELP!!
never [62]

Answer:

ITs a

Step-by-step explanation:

7 0
3 years ago
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