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Lelechka [254]
3 years ago
8

PLEASE HELP precal!

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
5 0
Check the picture below

so.. .hmmm the vertex is at the origin... and we know the parabola passes through those two points... let's use either.. say hmmm 100,-50, to get the coefficient "a"

keep in mind that, the parabolic dome is vertical, thus we use the y = a(x-h)²+k  version for parabolas, which is a vertical parabola

as opposed to x = (y-k)²+h, anyway, let's find "a"

\bf y=a(x-0)^2+0\implies y=ax^2\qquad 
\begin{cases}
x=100\\
y=-50
\end{cases}\implies -50=a100^2
\\\\\\
\cfrac{-50}{100^2}=a\implies -\cfrac{1}{200}=a
\\\\\\
thus\qquad \qquad y=-\cfrac{1}{200}x^2\implies \boxed{y=-\cfrac{x^2}{200}}

now.. .your choices, show.... a constant on the end.... a constant at the end, is just a vertical shift from the parent equation, the equation we've got above.. is just the parent equation, since we used the origin as the vertex, it has a vertical shift of 0, and thus no constant, but is basically, the same parabola, the one in the choices is just a shifted version, is all.


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Answer:

\displaystyle \frac{7x^2 + 4x - 20}{5x + 10} = \frac{7x - 10}{5}, x \neq -2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
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Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \frac{7x^2 + 4x - 20}{5x + 10}<u />

<u />

<u>Step 2: Simplify</u>

  1. [Frac - Numerator] Factor quadratic:                    \displaystyle \frac{(7x - 10)(x + 2)}{5x + 10}
  2. [Frac - Denominator] Factor GCF:                        \displaystyle \frac{(7x - 10)(x + 2)}{5(x + 2)}
  3. [Frac] Divide/Simplify:                                           \displaystyle \frac{(7x - 10)}{5}, x \neq -2

When we divide (x + 2), we would have a <em>removable</em> <em>discontinuity</em>. If we were to graph the original function, we would see at x = -2 there would be a hole in the graph.

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
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Answer:

The rocket hits the gorund after approximately 10.71 seconds.

Step-by-step explanation:

The height of the rocket <em>y</em> in feet <em>x</em> seconds after launch is given by the equation:

y=-16x^2+165x+69

And we want to find the time in which the rocket will hit the ground.

When it hits the ground, its height above ground will be 0. Hence, we can let <em>y</em> = 0 and solve for <em>x: </em>

<em />0=-16x^2+165x+69<em />

We can use the quadratic formula:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = -16, <em>b</em> = 165, and <em>c </em>= 69.

Substitute:

\displaystyle x=\frac{-165\pm\sqrt{(165)^2-4(-16)(69)}}{2(-16)}

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\displaystyle x=\frac{-165\pm\sqrt{31641}}{-32}=\frac{165\pm\sqrt{31641}}{32}

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\displaystyle x_1=\frac{165+\sqrt{31641}}{32}\approx 10.71\text{ or } x_2=\frac{165-\sqrt{31641}}{32}\approx-0.40

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