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Xelga [282]
3 years ago
13

How do you find a vector of length 10 in the direction of vequals=left angle 3 comma negative 2 right angle3,−2​?

Mathematics
1 answer:
Kazeer [188]3 years ago
4 0
First we look for the angle of the vector, which will be given by:
 tan (x) = (- 2/3)
 Clearing x we have:
 x = ATAN (-2/3) = - 33.69 degrees.
 Which means that the angle is 33.69 degrees measured clockwise from the x axis.
 Equivalently the angle is
 360-33.69 = 326.31 degrees
 326.31 degrees measured counterclockwise from the x axis.
 The vector is then:
 v = 10 (cos (326.31) i + sin (326.31) j)
 answer
 v = 10 (cos (326.31) i + sin (326.31) j)
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Can someone help me in this pretty please and asap!!! ;((
zepelin [54]

Answer:

(x -5)² + (y +4)² = 100 Should be the correct answer, hope this helps :)

Step-by-step explanation:

A circle centered at (h, k) with radius r will have equation ...

... (x -h)² + (y-k)² = r²

The point satisfies the equation for the circle. Filling in the given numbers, we have ...

... (x -5)² + (y+4)² = (-3-5)² + (2+4)² . . . . . . (h, k) = (5, -4), (x, y) = (-3, 2)

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6 0
3 years ago
WILL MARK BRAINIEST!!! Segment AC has two endpoints; (-2,5) and (2,-5). What are the coordinates of point B on segment AC such t
svet-max [94.6K]

Answer:

(\frac{4}{3},-\frac{10}{3})

Step-by-step explanation:

If the extreme ends of a line segment AC are A(x_1,y_1) and C(x_2,y_2).

If a point B(x, y) divides the segment in the ratio of m : n

Then the coordinates of the point B are,

x = \frac{mx_2+nx_1}{m+n}

y = \frac{my_2+ny_1}{m+n}

If the ends of AC are A(-2, 5) and C(2, -5) and a point B divides it in the ratio of m : n = 5 : 1

Therefore, coordinates of this point will be,

x = \frac{5\times (2)+1(-2)}{5+1}

  = \frac{10-2}{5+1}

  = \frac{8}{6}

  = \frac{4}{3}

y = \frac{5\times (-5)+1(5)}{5+1}

  = \frac{-25+5}{6}

  = -\frac{20}{6}

  = -\frac{10}{3}

Therefore, coordinates of the point B are (\frac{4}{3},-\frac{10}{3}).

6 0
3 years ago
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