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3 years ago

Janet borrowed 2000 for three years at a 5% interest rate compounded annually

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

4 0

A=p (1+r)^t
A=2,000×(1+0.05)^(3)
A=2,315.25

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A 2.5-kg water receives thermal energy of 36, 575 J. By how much its temperature increases?

coldgirl [10]

Answer:

water has a specific heat capacity of 4180 j/kg degree cellos

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3 years ago

How do write the number 100203 in word from

PIT_PIT [208]

100,203=>One hundred thousand, two hundred and three...

hope it helps !!!

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3 years ago

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A palm tree is supported by two guy wires as shown in the diagram below. Which trig expression can be used to find the height on

Volgvan

Answer:

D. $tan(30^\circ+45^\circ)$ is the correct answer.

Step-by-step explanation:

The given situation can be represented as a figure attached in answer area.

B is the base of tree.

C is the base of wires.

A and D are the end of 2 wires supporting the tree.

$\angle DCB =45^\circ\\\angle ACB =75^\circ\\$

Here, we need to find the Height of the tree which is represented the by side AB.

and we are given that bases of wires and tree base are at a distance 4 ft.

i.e. side BC = 4 ft

If we look at the $\triangle ABC$ , we are given the base BC and the $\angle ACB$ , and the perpendicular is to be find out.

We can use trigonometric identity:

$tan\theta =\dfrac{Perpendicular}{Base}$

$tan 75^\circ = \dfrac{AB}{BC}\\\bold {tan (45+30)^\circ }= \dfrac{AB}{4}\\\Rightarrow AB = \bold {tan (45+30)^\circ } \times 4 = 14.93\ ft$

Hence, D. $tan(30^\circ+45^\circ)$ is the correct answer.

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3 years ago

Consider th following formula used to find a cone v= 3.14r^2 h/3

lys-0071 [83]

Here's the volume formula (and the area formula) typed a little neater than that.
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3 years ago

The area of a circle is 616cm find the radius

Leokris [45]

<h3>Given :-</h3>

Area of Circle = 616 cm²

Radius of a circle = ?

<h3>Solution :-</h3>

☼︎ <u>Radius of the Circle</u>;

<h3>Using Formula:</h3>

$\\ \red\bigstar {\underline{\boxed{\color{springgreen}{\textsf{ \textbf{ \: Area \: of \: circle= \: \: π \: r \: ² \: }}}}}} \\\\$

<u>Putting values in the formula;</u>

$\\ \sf \implies \: Area \: = \: \pi \: r \: ^{2} \\$

$\\ \sf \implies \: 616 \: = \:\frac{22}{7} \times \: r \: ^{2} \\$

$\\ \sf \implies \: 616 \: \times \: \frac{7}{22} \: = \: \: r \: ^{2} \\$

$\\ \sf \implies \: \: \frac{ \: \: 4312 \: \: }{22} \: = \: \: r \: ^{2} \\$

$\\ \sf \implies \: \: \cancel{\frac{ \: \: 4312 \: \: }{22} }\: = \: \: r \: ^{2} \\$

$\\ \sf \implies \: \: \: 196 \: \: = \: \: r \: ^{2} \\$

$\\ \sf \implies \: \:r \: ^{2} = \: 196 \: \: \: \: \\$

$\\ \sf \implies \: \:r \: = \sqrt{ \: 196 \: } \\$

$\\ \bf \implies \: \:Radius \: = 14 \: cm \\$

henceforth, the Radius of a circle is 14 cm ...!!

6 0

2 years ago

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