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3 years ago

15

Please help!! I’ve been stuck on this question for 10 minutes! (Look at picture)

1 answer:

Darina [25.2K]3 years ago

5 0

Answer: 1/6a- 1/6

Step-by-step explanation:

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I need help is due in 20 minute

STALIN [3.7K]

The answers are B, D, F

$1.50+2=3.50$

$0.50+3=3.50$

$2.50+1=3.50$

7 0

4 years ago

There are 20 more dogs at the pet store than cats. If there are 7 cats, which equation can be used to find the number of dogs, d

crimeas [40]

Answer:

if d=dogs and c=cats then c+20=d

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Lucas is planting grass on the shaded portions of the yard. What will be the total area covered by grass?

maxonik [38]

Complete Question:

Lucas is planting grass on the shaded portions of the yard. What will be the total area of covered by grass? Fill in the missing.

Part A= 12 x ? = ? ft²

Part B= 0.5 x ? x 9 = ?ft²

Part C= 0.5 x 7 x ? = ?ft²

Total Area= ?ft²

Answer:

$A = 108ft^2$

$B = 27ft^2$

$C = 24.5ft^2$

$Area = 159.50ft^2$

Step-by-step explanation:

Given

See attachment

From the attachment;

Part A is a rectangle with dimension 9ft by 12ft

So,

$A = 12ft * 9ft$

$A = 108ft^2$

Part B is a triangle with dimension: height = 6 and base = 9

The height is calculated as:

$Height = 12ft - 6ft = 6ft$

And the base is:

$Base = 18ft - 9ft = 9ft$

So, the area is:

$B = 0.5 * 6ft * 9ft$

$B = 27ft^2$

Part C is a triangle with dimension: height = 7 and base = 7

So, the area is:

$C = 0.5 * 7 * 7ft^2$

$C = 24.5ft^2$

Total Area is:

$Area = A + B + C$

$Area = 108ft^2 + 27ft^2 + 24.5ft^2$

$Area = 159.50ft^2$

8 0

4 years ago

A particle starts at the point P=(−5,−1,3) when t=0 and moves along a straight line toward Q=(−6,−6,8) at a speed of 9 cm/sec. L

navik [9.2K]

Answer:

Step-by-step explanation:

Given

Particle moves from $P\ (-5,-1,3)\ to\ Q\ (-6,-6,8)$

speed of particle is $v=9\ cm/s$

Unit vector in the direction of vector $\vec{PQ}$ is given by

$\hat{n}=\frac{\vec{Q}-\vec{P}}{|\vec{Q}-\vec{P}|}$

$\hat{n}=\frac{-}{\sqrt{(-1)^2+(-5)^2+(5)^2}}$

$\hat{n}=\frac{}{\sqrt{1+25+25}}$

Now Position of Particle at any time is given by

$\vec{r(t)}=velocity\cdot time\cdot direction$

$\vec{r(t)}=9\cdot t\cdot \frac{}{\sqrt{1+25+25}}$

Parametric vector equation is given by

$x=\frac{-9t}{\sqrt{51}}$

$y=\frac{-45t}{\sqrt{51}}$

$z=\frac{45t}{\sqrt{51}}$

6 0

4 years ago

What is the median of the scores shown in the stem-and-leaf plot?

grin007 [14]

Here is the information for the stem-and-leaf plot you gave:
Median: 5
Range: 10
Mean: 6.08
Mode: 8
I don't see where the answers you provided would fit with this at all.

4 0

3 years ago