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Flauer [41]
2 years ago
15

Please help!! I’ve been stuck on this question for 10 minutes! (Look at picture)

Mathematics
1 answer:
Darina [25.2K]2 years ago
5 0

Answer: 1/6a- 1/6

Step-by-step explanation:

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A national organization sets out to investigate the change in prevalence of HIV since the last census in 2010. A total of 4,706
nikitadnepr [17]

Answer:

As can be seen, there has been a rise in the proportion of the population with HIV positive, from 7.5% to 9.94%.

Step-by-step explanation:

Given that a national organization sets out to investigate the change in prevalence of HIV since the last census in 2010, ya total of 4,706 participants were interviewed and a total of 468 responses were confirmed to be HIV positive, assuming that the data from the census indicated that the prevalence of HIV in the particular population was 7.5%, to determine if the proportion of the prevalence of HIV has changed (is equal to 7.5%) the following calculation should be performed:

4706 = 100

468 = X

468 x 100/4706 = X

46,800 / 4,706 = X

9.94 = X

Therefore, as can be seen, there has been a rise in the proportion of the population with HIV positive, from 7.5% to 9.94%.

4 0
2 years ago
Solve the equation<br><br><br> 12 - 27n2 = 0<br> 9, 3<br> (2/3), (-2/3)<br> (3/2), (-3/2)<br> 2, 3
Norma-Jean [14]
(2/3),=(1/2), 3,4
.
............................
4 0
2 years ago
(1+y) (4y+6) =0 algebra 2
marta [7]
Here is your answer! Hope this helped

5 0
2 years ago
The function Q(x)=2x^2-kx+18. For what value of k does Q(x) have one distinct real solution? (NEEDS TO BE DONE WITHIN 2 HOURS!)
Aliun [14]

Answer:

k = 12

Step-by-step explanation:

Given:

The equation Q(x)=2x^2-kx+18

To find:

Value of k = ? for which the given equation has one distinct real solution.

Solution:

The given equation is a quadratic equation.

There are always two solutions of a quadratic equation.

For the equation: ax^{2} +bx+c=0 to have one distinct solution:

b^2 - 4ac = 0

Here,

a = 2,

b = -k and

c = 18

Putting the values, we get:

(-k)^2 - 4\times 2\times 18 = 0\\\Rightarrow k^2 = 18\times 8\\\Rightarrow k^2 =144\\\Rightarrow k = 12

The equation becomes:

Q(x)=2x^2-12x+18

And the one root is:

2(x^2-6x+9 ) = 0\\\Rightarrow 2(x-3)^2=0\\\Rightarrow x = 3

4 0
2 years ago
5. How many real number solutions does the equation have?
sukhopar [10]

Answer:

two solutions

Step-by-step explanation:

it's a square equations and has two answers

5 0
3 years ago
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