Since this is an obtuse triangle, Point O is not equidistant from A, B, and C. Point O is not on the perpendicular bisectors, so the third statement is true. Point O is equidistant from AB, BC, and CA because these lines are pressed against the circpe in a mannered way.
Answer:



Step-by-step explanation:
Given




Required
The dimension that minimizes the cost
The volume is:

This gives:

Substitute 


Make H the subject


The surface area is:
Area = Area of Bottom + Area of Sides
So, we have:

The cost is:



Substitute:
and 



To minimize the cost, we differentiate

Then set to 0


Rewrite as:

Divide both sides by W

Rewrite as:

Solve for 


Take cube roots

Recall that:







Hence, the dimension that minimizes the cost is:



The triangle is kinda square so multiply and you should get 24
It's easy once you spot the ones that can cross cancel!
Say we have the fractions 8/10 and 20/23.
(it's easier to see on top of each other)
If you look diagonally , so 8 and 23 and 10 and 20, you can see that 10 and 20 have a common factor. So we divide it by the highest common factor to reduce those numbers, making it easier to multiply. 10 and 20 can become 1 and 2, dividing by 10. So now we are left with 8/1 and 2/23, and now we multiply normally going across so 16/23.
This works going both diagonals and simplifying both, but in that case it would be easier to try and simplify the fractions before cross multiplying them.
Basically: look for those diagonals and if they can be divided down by the highest common factor, go for it to make it easier to multiply normally afterwards.
Hope I helped!