Tonisha is purchasing a number of stamps. She wants some idea of how many she can buy.

Which values are solutions 4x greater than or equal to 35

Mamont248 [21]

Answer:

$\frac{5}{1/2}$ , 12, $\frac{8}{3/4}$ , 10

Step-by-step explanation:

$4x\geq 35$

$x \geq \frac{35}{4}$

$x \geq 8 \frac{3}{4}$

so

$\frac{5}{1/2}$ = 10

12

$\frac{8}{3/4}$ = 10.66

and 10

Because saying 5 over 1/2 is saying 5 divided by 1/2 which is the same as saying 5 * 2

8 over 3/4 is 8 divided by 3/4 which is 8 * 1.33.

A fraction is division. If you mean 5 and 1/2 as well as 8 and 3/4 then remove 5 and 1/2 from the answer.

6 0

3 years ago

Plz answer my question it is urgent..!!

oee [108]

Answer:

In the step-by-step explanation!

Step-by-step explanation:

Not sure if it is too late but here:

1.)

$\frac{1}{\alpha}+\frac{1}{\beta} \\\frac{\beta}{\alpha \beta } +\frac{\alpha}{\alpha \beta } \\\frac{\alpha +\beta }{\alpha \beta }$

2.)

$\frac{1 }{\alpha } *\frac{1}{\beta} = \frac{1*1}{\alpha*\beta} =\frac{1}{\alpha \beta}$

3.)

$\frac{1}{\alpha}-\frac{1}{\beta}\\ \frac{\beta}{\alpha \beta } -\frac{\alpha }{\alpha \beta } \\\frac{\beta -\alpha }{\alpha \beta }$

Hopes this help! Please give me Brainliest!

6 0

3 years ago

Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?

likoan [24]

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=15,\:\quad a_n=2$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}$

$-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3$

$\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5$

$=\left(x+3\right)\left(2x^2-11x+5\right)$

$Factor: 2x^2-11x+5$

$2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)$

$=x\left(2x-1\right)-5\left(2x-1\right)$

$2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)$

$\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:}$

thus zeros of f(x) is

$x=-3,\:x=5,\:x=\frac{1}{2}$

5 0

3 years ago

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(6x-3y - 12<br> - (2x+2y=10

madreJ [45]

Answer:

8x - 5y - 13

Step-by-step explanation:

(6x - 3y - 12) - (2x +2y - 10)

(6x - 3y - 12) - 2x - 2y + 10

6x - 3y - 23 - 2x - 2y + 10

8x - 5y - 13

8 0

3 years ago

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Tyre measured the average monthly temperature in degrees Fahrenheit for several months. If February is set ect 2 and June is oud

Katena32 [7]

Answer:

it will be d

Step-by-step explanation:

7 0

3 years ago

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