Answer:
(x-2)(y+1)
Step-by-step explanation:
Answer: a - 4.512 hours
b - 1.94 hours
Step-by-step explanation:
Given,
a) A(t) = 10 (0.7)^t
To determine when 2mg is left in the body
We would have,
A(t) = 2, therefore
2 = 10(0.7)^t
0.7^t =2÷10
0.7^t = 0.2
Take the log of both sides,
Log (0.7)^t = log 0.2
t log 0.7 = log 0.2
t = log 0.2/ 0.7
t = 4.512 hours
Thus it will take 4.512 hours for 2mg to be left in the body.
b) Half life
Let A(t) = 1/2 A(0)
Thus,
1/2 A(0) = A(0)0.7^t
Divide both sides by A(0)
1/2 = 0.7^t
0.7^t = 0.5
Take log of both sides
Log 0.7^t = log 0.5
t log 0.7 = log 0.5
t = log 0.5/log 0.7
t = 1.94 hours
Therefore, the half life of the drug is 1.94 hours
Answer:
Option D. 
Step-by-step explanation:
In this problem
we have
where
B is the Final Investment Value or a Balance
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
in this problem we have
substitute in the formula above
The x coordinate is halfway between 2 and 10 = 2 + (10-2)/2 = 2+4 = 6
so midpoint is C (6,3)
answer
20h = 942.857
15h= 707.14
Step-by-step explanation:
