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3 years ago

John goes to a restaurant and has a bill of $32.57. He uses a 10% off coupon on

Mathematics

1 answer:

otez555 [7]3 years ago

5 0

Answer:

<u>John spends $ 37.98</u>

Step-by-step explanation:

1. John has a bill of $ 32.57

2. He leaves a tip of 18% on the amount before the coupon or tax is applied, in consequence: 32.57 + 18% (32.57) = 32.57 + 5.86 = 38.43

3. He uses a 10% off coupon on the cost of the meal, therefore:

38.43 - 10% (32.57) = 38.43 - 3.26 = 35.17

4. The tax is 8%, then:

35.17 + 8% (35.17) = 35.17 + 2.81 = 37.98

<u>John spends $ 37.98</u>

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2 years ago

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3 years ago

If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds a

Luba_88 [7]

Answer:

$12C5 *(12C3) = 792*220 =174240 ways$

Step-by-step explanation:

For this case we know that we have 12 cards of each denomination (hearts, diamonds, clubs and spades) because 12*4= 52

First let's find the number of ways in order to select 5 diamonds. We can use the combinatory formula since the order for this case no matter. The general formula for combinatory is given by:

$nCx = \frac{n!}{x! (n-x)!}$

So then 12 C5 would be equal to:

$12C5 = \frac{12!}{5! (12-5)!}=\frac{12!}{5! 7!} = \frac{12*11*10*9*8*7!}{5! 7!}= \frac{12*11*10*9*8}{5*4*3*2*1}=792$

So we have 792 was in order to select 5 diamonds from the total of 12

Now in order to select 3 clubs from the total of 12 we have the following number of ways:

$12C3 = \frac{12!}{3! 9!}=\frac{12*11*10*9!}{3! 9!} =\frac{12*11*10}{3*2*1}=220$

So then the numbers of ways in order to select 5 diamonds and 3 clubs are:

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2 years ago

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vitfil [10]

1. all functions are relations.

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3.
f(n) = n² - n f(-4)
f(-4) = -4² - (-4)
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hope this helped, God bless!

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2 years ago