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Neporo4naja [7]
3 years ago
5

Find x and y thanks :D

Mathematics
1 answer:
Alika [10]3 years ago
8 0
So wyou said she was going to
You might be interested in
(5•10^-2) x (2•10^3)
Andre45 [30]

Answer:

100

Step-by-step explanation:

5•10^-2= 5•1/100 an d that's equal to 1/20 if you divide it with (2•10^3)wich is equal too 2000

you will get 100 as a result

6 0
3 years ago
Read 2 more answers
Simplify the expression.
Tamiku [17]

Answer:

\boxed{=144--> C.}

Step-by-step explanation:

<u><em>You had to used pemdas stands for: p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract that came from left to right.</em></u>

First you calculate with parenthesis first.

(13-1)^2/2

12^2/2

Then you calculate with exponents.

12^2=12*12=144

144/2

Next, divide from left to right.

144/2=72

144/72=2

72*2=144

2*72=144

=72

2*72

Finally, multiply from left to right.

72*2=144

12*12=144

Final answer: \boxed{=144}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

3 0
3 years ago
Bruce bought two books one book cost $4.00 more than three times the other . Together, the two books cost him $72
VikaD [51]
One is $12 the other is $72
7 0
3 years ago
Suppose a coin is flipped and a card is drawn from the deck. What is the probability that the coin lands on tails and the card i
Deffense [45]

Answer:

1/26

Step-by-step explanation:

1 out of 13 would be equal to the amount of cards that would be a jack.

But you also have to take into regards the coin flip 50%chance so you would just could what the number is divided by to get the right answer. Since out come could be tails or head instead of just being one for sure for example.

5 0
3 years ago
Find the mean median mode and range for the following data 77 60 59 70 89 95
Advocard [28]

Answer:

Mean = 75

Median = 73.5

Mode = 95

Range = 36

Step-by-step explanation:

Given:

  • 77,60,59,70,89,95

Sort:

  • 59,60,70,77,89,95

To find:

  • Mean
  • Median
  • Mode
  • Range

Mean:

\displaystyle \large{\dfrac{1}{n}\sum_{i =1}^n x_i = \dfrac{x_1+x_2+x_3+...+x_n}{n}}

Sum of all data divides by amount.

\displaystyle \large{\dfrac{59+60+70+77+89+95}{6}=\dfrac{450}{6}}\\\\\displaystyle \large{\therefore mean=75}

Therefore, mean = 75

Median:

If it’s exact middle then that’s the median. However, if two data or values happen to be in <em>middle</em>:

\displaystyle \large{\dfrac{x_1+x_2}{2}}

From 59,60,70,77,89,95, since 70 and 77 are in middle:

\displaystyle \large{\dfrac{70+77}{2} = \dfrac{147}{2}}\\\displaystyle \large{\therefore median = 73.5}

Therefore, median = 73.5

Mode:

The highest value or/and the highest amount of data. Mode can have more than one.

From sorted data, there are no repetitive data nor same data. Consider the highest value:

Therefore, mode = 95

Range:

\displaystyle \large{x_{max}-x_{min}} or highest value - lowest value

Thus:

\displaystyle \large{95-59 = 36}

Therefore, range = 36

7 0
2 years ago
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