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leonid [27]
3 years ago
6

A red card is drawn from a standard deck of 52 playing cards. If the red card is not replaced, find the probability of drawing a

second card that is black. P(black|red)
Mathematics
1 answer:
babunello [35]3 years ago
8 0

Answer:

26/51

Step-by-step explanation:

Probability Formula = No of possible events ÷ Number of events

We are given a standard deck of 52 cards. Hence,

The number of events = 52

It is important to note that in a standard deck of 52 playing cards,

26 are red

26 are black

WITHOUT REPLACEMENT

Probably of drawing

a red card = 26/52 = 1/2

We are asked to find the probability of drawing a second card that is black

Probability of drawing a black card = No of possible outcomes / Number of events

Number of possible outcomes = 26 Due to the fact that the red card after been drawn was not replaced,

Number of events = 51

Hence , Probability of drawing a black card = 26/51

Therefore, the Probability of drawing a black card =

P (black ) = 26 /51

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Y=3x+4 , 9x-3y=-6 do the lines intersect or are they parallel or are they perpendicular
Angelina_Jolie [31]

Answer:

Lines are parallel.

Step-by-step explanation:

The given lines are y=3x+4,\ 9x-3y=6

Rearrange the equation in the slope intercept form that is y=mx+b where m is the slope.

<em>First Line:</em>

y=3x+4

compare it with y=mx+b

slope (m_{1}) of first line =3

<em>Second Line:</em>

9x-3y=6\\9x-6=3y\\3y=9x-6

divide both by 3

y=3x-3

compare it with y=mx+b

slope (m_{2}) of second line =3

Since slope of two lines are equal

m_{1}=m_{2}=3

hence these lines are parallel.

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3 years ago
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3 years ago
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emmasim [6.3K]

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Step-by-step explanation:

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How can one halfx − 5 = one thirdx + 6 be set up as a system of equations? 2y + x = −10 3y + x = 18 2y + 2x = −10 3y + 3x = 18 2
Doss [256]

Answer:

2y-x= -10

3y-x = 18

Step-by-step explanation:

The correct option is . 2y-x = -10 ,  3y-x = 18

one half x − 5 = 1/2 (x-5)

one third x + 6 = 1/3 *(x+6)

1/2 x-5 = 1/3x+6 =y

y= 1/2x-5

y = 1/3x+6

Now,

y=x/2 -5     equation 1

y = x/3 +6    equation 2

By taking L.C.M of the first equation we get:

y=x/2 -5

y= x-10/2

Now multiply both terms by 2.

2y=x-10

2y-x= -10

Now lets solve second equation:

Take L.C.M of the second equation:

y = x/3 +6

y=x+18/3

Multiply both sides by 3

3y= x+18

3y-x = 18

Therefore the system of equations we get is:

2y-x= -10

3y-x = 18 ....

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