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nikitadnepr [17]
3 years ago
14

Miguel Rodriguez borrowed ​$200 from his brother Julio to pay for books and tuition. He agreed to pay Julio in 6 months with sim

ple annual interest at 6.8​%.
​a) How much will the interest amount​ to?
​b) What amount must Miguel pay Julio at the end of 6​ months?

The simple interest is ​$
Mathematics
2 answers:
ahrayia [7]3 years ago
7 0

Answer:

simple interest is $6.8

Miguel pay amount to Julio at the end of 6​ months $206.8

Step-by-step explanation:

Given : Miguel Rodriguez borrowed ​$200 from his brother Julio to pay for books and tuition. He agreed to pay Julio in 6 months with simple annual interest at 6.8​%.


To Find : ​a) How much will the interest amount​ to?


​b) What amount must Miguel pay Julio at the end of 6​ months?


Solution :

Formula for simple interest :

S.I. = principal*rate*time

Where rate is in decimal

Time is in years

So, rate of interest = 6.8 % = 0.068

Time = 6 months = \frac{6}{12} = 0.5 years

Principal = $200

Thus S.I. = 200*0.068*0.5

S.I. = 6.8

Now To calculate  amount must Miguel pay Julio at the end of 6​ months

Amount = principal +Simple interest

Amount = 200+6.8 =206.8

Hence the simple interest is $6.8

And Miguel pay amount to Julio at the end of 6​ months $206.8

goblinko [34]3 years ago
3 0
A)6/12 *.068=.034
b)200 + 200(.034)=$206.80 due at 6 months
☺☺☺☺
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ANSWER :

Surface area of larger cone : 24π units^2

Surface area of smaller cone : 6π units^2

The surface area of the smaller cone is 25% of that of the larger cone.

EXPLANATION :

From the given problem,

AB = 3 is the radius of the larger cone and the slanted height is BC = 5

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Recall the surface area of the cone :

A=\pi r^2+\pi rL

where r = radius and L = slanted height.

For the larger cone, r = 3 and L = 5

\begin{gathered} A=\pi(3)^2+\pi(3)(5) \\ A=24\pi \end{gathered}

For the smaller cone, r = 1.5 and L = 2.5

\begin{gathered} A=\pi(1.5)^2+\pi(1.5)(2.5) \\ A=6\pi \end{gathered}

Comparing the surface areas :

The area of the smaller cone compared to the larger cone is :

\begin{gathered} \frac{smaller}{larger}\times100=\frac{6\pi}{24\pi}\times100 \\  \\ =25\% \end{gathered}

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Step-by-step explanation:

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