Use a calculator to find the cube root of positive or negative numbers. Given a number x<span>, the cube root of </span>x<span> is a number </span>a<span> such that </span><span>a3 = x</span><span>. If </span>x<span> positive </span>a<span> will be positive, if </span>x<span> is negative </span>a<span> will be negative. Cube roots is a specialized form of our common </span>radicals calculator<span>.
</span>Example Cube Roots:<span>The 3rd root of 64, or 64 radical 3, or the cube root of 64 is written as \( \sqrt[3]{64} = 4 \).The 3rd root of -64, or -64 radical 3, or the cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).The cube root of 8 is written as \( \sqrt[3]{8} = 2 \).The cube root of 10 is written as \( \sqrt[3]{10} = 2.154435 \).</span>
The cube root of x is the same as x raised to the 1/3 power. Written as \( \sqrt[3]{x} = x^{\frac{1}{3}} \). The common definition of the cube root of a negative number is that <span>
(-x)1/3</span> = <span>-(x1/3)</span>.[1] For example:
<span>The cube root of -27 is written as \( \sqrt[3]{-27} = -3 \).The cube root of -8 is written as \( \sqrt[3]{-8} = -2 \).The cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).</span><span>
</span>This was not copied from a website or someone else. This was from my last year report.
<span>
f -64, or -64 radical 3, or the cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).The cube root of 8 is written as \( \sqrt[3]{8} = 2 \).The cube root of 10 is written as \( \sqrt[3]{10} = 2.154435 \).</span>
The cube root of x is the same as x raised to the 1/3 power. Written as \( \sqrt[3]{x} = x^{\frac{1}{3}} \). The common definition of the cube root of a negative number is that <span>
(-x)1/3</span> = <span>-(x1/3)</span>.[1] For example:
<span>The cube root of -27 is written as \( \sqrt[3]{-27} = -3 \).The cube root of -8 is written as \( \sqrt[3]{-8} = -2 \).The cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).</span>
Answer:
r= 1.69
Step-by-step explanation:
Answer:
x = 100
Step-by-step explanation:
The larger area is ...
A = LW
A = (300+x)(200+x) = x^2 +500x +60,000
The smaller area is ...
A = (200)(300) = 60,000
We want the larger area to be double the smaller area, so ...
x^2 +500x +60,000 = 2(60,000)
x^2 +500x = 60,000 . . . . . . . . . . . . subtract 60,000
x^2 +500x + 62500 = 122500 . . . add 250^2 to complete the square
(x +250)^2 = 350^2
We're interested in the positive solution, so we can take the positive square root to find it:
x +250 = 350
x = 100 . . . . . . . . . subtract 250
_____
The graph shows the quadratic in the form x^2 +500x -60,000. That is, we're looking for zeros (x-intercepts) of the function.
To make sure you do this correctly, first i would suggest separating the 3 and the x
3•x^3/8
For a fractional exponent, the denominator is the root you take of the number (in this case the eight root) and the numerator is the exponent of the number under the radical.
3• ^8√x^3
Sorry that's a little messy, it's the best i can do on my phone!!
The multiplication symbol ( • ) is not necessary, I just put it there to make things more clear.
Hope this helps!
Answer:
7/20
Step-by-step explanation:
GIven:
Battery A = 4/5 remaining
Battery B = 9/20 remaining
assuming both batteries are otherwise identical (except for charge level remaining), then,
Battery A - Battery B
= 4/5 - 9/20
we need to convert both fractions to same denominator to perform the subtraction easily. Note that the Least Common Multiple for 5 and 20 is 20, hence we convert both denominators to 20,
Battery A - Battery B
= 4/5 - 9/20
= (4/5) (4/4) - 9/20
= 16/20-9/20
= 7/20
