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shutvik [7]
4 years ago
15

Andrew is evaluating his current financial position by totaling his monthly cash inflows and outflows. His cash inflows each mon

th are $60 in allowance and $240 in wages from his part-time job working at the pet store. His cash outflows each month are $170 for his car payment, $70 in entertainment, and $45 for gas and food. How much, if anything, does Andrew have left over each month?
Mathematics
1 answer:
Zarrin [17]4 years ago
3 0
15 dollars left each month
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Solve the inequality
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\huge\text{Hey there!}

\mathsf{\dfrac{x}{4}\geq-6}

\large\text{SUBSITUTE 1 where x is at temporarily, so we can simplify both}\\\large\text{sides of your inequality}

\large\text{NEW EQUATION: }\mathsf{\dfrac{1}{4}x \geq-6}

\large\text{MULTIPLY by 6 to BOTH SIDES}

\mathsf{4\times\dfrac{}{}x \geq 4\times-6}

\large\text{CANCEL out: }\mathsf{4\times\dfrac{1}{4}}\large\text{ because that gives you the value of 1}

\large\text{KEEP: }\mathsf{4\times-6}\large\text{ because it helps you find out the number or value}\\\large\text{that is being compared to your x-value}

\mathsf{4\times-6=\boxed{\bf -24}}

\large\text{So, the number \underline{-24} is being compared to your x-value}

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\boxed{\boxed{\large\text{Answer: \bf x}\bf \geq\large\textsf{\bf -24 \huge\text{Option D.}}}}\huge\checkmark

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4 0
3 years ago
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The probability Brenda will recieve a telemarketing call is 15%. If she gets 20 calls a day, how many can she expect to be telem
Arturiano [62]

Answer:

3 telemarketing calls

Step-by-step explanation:

First convert 15% to a decimal:

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let x = number of calls

Build an expression

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substitute our value for x (20 calls)

20(.15) = 3

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Step-by-step explanation:

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Angelina_Jolie [31]

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Step-by-step explanation:

YW

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4 years ago
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This problem addresses some common algebraic errors. For the equalities stated below assume that x and y stand for real numbers.
weqwewe [10]

Answer:

The answers are:

a) (x+y)^2 = x^2 + y^2 is FALSE.

b) (x+y)^2 = x^2 + 2xy + y^2 is TRUE.

c) \frac{x}{x+y}= \frac{1}{y} is FALSE.

d) x-(x+y) = y is FALSE.

e) \sqrt{x^2} = x is FALSE.

f) \sqrt{x^2} = |x| is TRUE.

g) \sqrt{x^2+4} = x+2 is FALSE.

h) \frac{1}{x+y} = \frac{1}{x} + \frac{1}{y} is FALSE.

Step-by-step explanation:

We can show that the FALSE statement are, in fact, false finding an example where the equality fails.

a) Take x=2 and y=3 and notice that (2+3)² = 25, while 2²+3²=4+9=13.

b) (x+y)² = (x+y)(x+y)=x²+xy+xy+y² = x² +2xy +y².

c) Take x=2 and y=3 and notice that 2/(2+3) = 2/5 which is different from 1/3.

d) Take x=2 and y=3 and notice that 2-(2+3) = 2-5=-3 which is different from 3. Recall that x-(x+y) = x-x-y=-y.

e) Take x=-2, and notice that [tax]\sqrt{(-2)^2} = \sqrt{4} = 2[/tex] which is different from -2.

f) The previous example illustrate why this is true.

g) Take x=1, and notice that sqrt{1^2+4} = \sqrt{5} which is different from 3.

h) Take x=2 and y=3 and notice that 1/(2+3)=1/5 and 1/3+1/2 = 5/6.

3 0
3 years ago
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