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2 years ago

Carlos has $24, which is 1 1/3 as much money as Luisa has. How much money does Luisa have?

Mathematics

2 answers:

aliina [53]2 years ago

7 0

Answer:

Luisa has $18

Step-by-step explanation:

Let us solve the question

∵ Carlos has $24

∵ Carlos has 1 $\frac{1}{3}$ as much money as Luisa has

→ Let Luisa has x dollars

∵ Luisa has x dollars

∴ Carlos money = 1 $\frac{1}{3}$ × x

∴ Carlos money = 1 $\frac{1}{3}$ x

→ Change the mixed number to an improper fraction

∵ 1 $\frac{1}{3}$ = $\frac{1(3)+1}{3}$ = $\frac{4}{3}$

∴ Carlos money = $\frac{4}{3}$ x

→ Substitute the Carlos money by 24

∵ 24 = $\frac{4}{3}$ x

→ Multiply both sides by 3

∵ 24 × 3 = 4x

∴ 72 = 4x

→ Divide both sides by 4

∴ 18 = x

∴ Luisa has $18

Goryan [66]2 years ago

4 0

Answer:

18 bucks

Step-by-step explanation:

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Answer:

For f(x) = √(2·x + 2) - √(x + 18), at f(x) = -1 the possible x-values includes;

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Step-by-step explanation:

Given that the function is f(x) = √(2·x + 2) - √(x + 18)

The value of 'x' when f(x) = -1, is given as follows;

-1 = √(2·x + 2) - √(x + 18)

-1² = (√(2·x + 2) - √(x + 18))² = 3·x + 20 - 2·√(2·x + 2)×√(x + 18)

1 = 3·x + 20 - 2·√(2·x + 2)×√(x + 18)

2·√(2·x + 2)×√(x + 18) = 3·x + 20 - 1 = 3·x + 19

2·x² + 38·x + 36 = (3·x + 19)/2

2·x² + 38·x + 36 - (3·x + 19)/2 = 0

4·x² + 73·x + 53 = 0

From which we get;

x = (-73 ± √(73² - 4 × 4 × 53))/(2 × 4)

x ≈ -0.757, and x ≈ -17.5

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