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4 years ago

PLZ HELP I AM FAILING AND NEED HELP!!!!

Mathematics

1 answer:

MA_775_DIABLO [31]4 years ago

5 0

Answer: About 13% of the school would be in chess club.

Step-by-step explanation: Out of 85 students, 11 were in chess club. So:

11 / 85 = 0.1294117647, or approximately 13%.

If it's not too much to ask, may I have brainliest?

You might be interested in

Find the value of R so that the line that passes through each pair of points has the given slope: (8, -2 ), (r, -6), m=-4

kondor19780726 [428]

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 8}}\quad ,&{{ -2}})\quad 
% (c,d)
&({{ r}}\quad ,&{{ -6}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-6-(-2)}{r-8}=-4
\\\\\\
\cfrac{-6+2}{r-8}=-4\implies -4=-4(r-8)\implies \cfrac{-4}{-4}=r-8\\\\\\ 1+8=r$

8 0

3 years ago

How can you use mental math to find the percent of a number?

olga_2 [115]

Every percent of that number is 1/100 of that number
Example 30, 1/100 of 30 is .30
Example 100, 1/100 of 100 is 1
Example 52, 1/100 of 52 is .52

3 0

3 years ago

Help me plz quick my phone about to die

konstantin123 [22]

I'll do the first graph.

We can easily find the y intercept by inputting 0 for x.

y = -2(0) + 7
y = 7

The y-intercept is (0, 7)

To find the x intercept, isolate x.

y = -2x + 7
Add 2x to both sides.
2x + y = 7
Subtract y from both sides.
2x = -y + 7
Divide by 2 on both sides.
x = -1/2y + 3.5

Input 0 for y.

x = -1/2(0) + 3.5
x = 3.5

The x intercept is (3.5, 0)

Now try the rest own your own! :)

5 0

4 years ago

A baker is deciding how many batches of muffins to make to sell in his bakery. He wants to make enough to sell every one and no

Morgarella [4.7K]

Answer:

$P(x = 1) = 0.10$

Step-by-step explanation:

Given

$\begin{array}{ccccc}x & {1} & {2} & {3} & {4} \ \\ P(x) & {0.10} & {0.30} & {0.40} & {0.20} \ \ \end{array}$

Required

Determine the probability of selling exactly 1 batch

This probability is represented with $P(x = 1)$

From the table:

When x = 1; P(x) = 0.10

Hence:

$P(x = 1) = 0.10$

In other words, the probability of selling exactly 1 is 0.10

7 0

3 years ago

Lim n-> infinity [1/3 + 1/3² + 1/3³ + . . . .+ 1/3ⁿ]

Verizon [17]

Answer:

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm :\longmapsto\:\displaystyle\lim_{n \to \infty }\rm \bigg[\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} } \bigg]$

Let we first evaluate

$\rm :\longmapsto\:\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} }$

Its a Geometric progression with

$\rm :\longmapsto\:a = \dfrac{1}{3}$

$\rm :\longmapsto\:r = \dfrac{1}{3}$

$\rm :\longmapsto\:n = n$

So, Sum of n terms of GP series is

$\rm :\longmapsto\:S_n = \dfrac{a(1 - {r}^{n} )}{1 - r}$

$\rm :\longmapsto\:S_n = \dfrac{1}{3} \bigg[\dfrac{1 - {\bigg[\dfrac{1}{3} \bigg]}^{n} }{1 - \dfrac{1}{3} } \bigg]$

$\rm :\longmapsto\:S_n = \dfrac{1}{3} \bigg[\dfrac{1 - {\bigg[\dfrac{1}{3} \bigg]}^{n} }{\dfrac{3 - 1}{3} } \bigg]$

$\rm :\longmapsto\:S_n = \dfrac{1}{3} \bigg[\dfrac{1 - {\bigg[\dfrac{1}{3} \bigg]}^{n} }{\dfrac{2}{3} } \bigg]$

$\bf\implies \:S_n = \dfrac{1}{2}\bigg[1 - \dfrac{1}{ {3}^{n} } \bigg]$

Hence, 

$\bf :\longmapsto\:\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} } = \dfrac{1}{2}\bigg[1 - \dfrac{1}{ {3}^{n} } \bigg]$

Therefore, 

$\purple{\rm :\longmapsto\:\displaystyle\lim_{n \to \infty }\rm \bigg[\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} } \bigg]}$

$\rm \: = \: \displaystyle\lim_{n \to \infty }\rm \dfrac{1}{2}\bigg[1 - \dfrac{1}{ {3}^{n} } \bigg]$

$\rm \: = \: \rm \dfrac{1}{2}\bigg[1 - 0 \bigg]$

$\rm \: = \: \rm \dfrac{1}{2}$

Hence, 

$\purple{\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{n \to \infty }\rm \bigg[\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} } \bigg]} = \frac{1}{2}}}$

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<h3>Explore More</h3>

$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{sinx}{x} = 1}}$

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$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{ {e}^{x} - 1}{x} = 1}}$

$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{ {a}^{x} - 1}{x} = loga}}$

8 0

3 years ago