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3 years ago

What is the value of x?

Mathematics

1 answer:

vivado [14]3 years ago

5 0

Answer:

x = 52/3

Step-by-step explanation:

3x / 7x = (3x+7) / (3x+7+5x-8)

3/7 = (3x+7)/(8x - 1)

Cross multiply

7(3x+7)=3(8x-1)

21x + 49 = 24x - 3

-3x = -52

x = 52/3

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Help I’m confused on this

Delvig [45]

Add all the numbers:

36 + 10 + 2 + 20 + 26 + 6 = 100

Count the amount of female:

20 + 26 + 6 = 52

Female out of total = 52/100

if you have to simplify, its going to be 13/25

Hope this helped☺☺

6 0

3 years ago

Read 2 more answers

The length of a rectangle is four more than three times its width. the area of the rectangle is 25. write an algebraic model for

Dafna11 [192]

width (w) = w

Length (L) = 3w + 4

Area (A) = L x w

25 = (3w + 4)w

25 = 3w² + 4w

0 = 3w² + 4w - 25

w = $\frac{-2 +/-\sqrt{79} }{3}$

w ≈ 2.3, w ≈ -3.6 (width cannot be negative!)

w ≈ 2.3

Length (L) = 3w + 4 = 3(2.3) + 4 = 6.9 + 4 = 10.9

Answer: width=2.3, Length=10.9

4 0

2 years ago

Can you answer these for me ?

vodka [1.7K]

Answer:

B. 4 3/8

Step-by-step explanation:

7/8 X 5 = 4 3/8

6 0

2 years ago

Y/−7 = 1 /4 what does y =

Studentka2010 [4]

Answer:

y = - $\frac{7}{4}$

Step-by-step explanation:

$\frac{y}{-7}$ = $\frac{1}{4}$ ( cross- multiply )

4y = - 7 ( divide both sides by 4 )

y = - $\frac{7}{4}$

4 0

2 years ago

Read 2 more answers

Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball

Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and $51\frac{1}{3}$ yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from $51\frac{1}{3}$ yards.

$\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}$

Let us have a common denominator.

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}$

$\text{1 yard}=3\text{ feet}$

$\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}$

$\frac{28}{3}\text{ yards}=28\text{ feet}$

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0

3 years ago