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jekas [21]
2 years ago
13

Which of the following is most likely the next step in the series? ​

Mathematics
1 answer:
kolbaska11 [484]2 years ago
7 0

Answer:

a

Step-by-step explanation:

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Muriel says she has written a system of two linear equations that has an infinite number of solutions. One of the equations of t
Natalka [10]

Answer:

B is correct

Step-by-step explanation: an infinite number of solutions means a coincident line...it is the same line

3y = 2x - 9...divide by 3

y = 2/3x - 3...hmm...same line as answer choice b....they are coincident lines and have infinite solutions

7 0
3 years ago
Read 2 more answers
A student has $1 bills and $5 bills in his wallet. He had a total of 15 bills that are worth $47. How many of each type does he
Mrrafil [7]

Total number of $1 bills=7

Total number of $5 bills=8

Further explanation:

Given

Let x be the number of $1 bills

and

y be the number of $5 bills

Then according to the given statements

x+y=15

x+5y=47

From first equation:

x+y=15\\x=15-y

Putting x=15-y in second equation

x+5y=47\\15-y+5y=47\\4y=47-15\\4y=32\\\frac{4y}{4}=\frac{32}{4}\\y=8

Putting y=8 in first equation

x+8=15\\x=15-8\\x=7

Hence,

Total number of $1 bills=7

Total number of $5 bills=8

Keywords: Linear equations, Substitution method

Learn more about linear equations at:

  • brainly.com/question/2367554
  • brainly.com/question/2977815

#LearnwithBrainly

4 0
3 years ago
(-4) (-4) rewrite expression use exponent rather then repeating multiplication
vekshin1

Answer:4^2 or (-4)^2

Step-by-step explanation:

I don't really know how to explain it. I can try if you want

4 0
3 years ago
Select the pair of slopes that are the slopes of perpendicular lines.
agasfer [191]
<h3>\frac{3}{4}\ and\ \frac{-4}{3} are the slopes of perpendicular lines</h3>

<em><u>Solution:</u></em>

We know that,

Product of slope of a line and slope of line perpendicular to it is always equal to -1

<em><u>Option 1</u></em>

\frac{1}{2}\ and\ 2

Product = \frac{1}{2} \times 2 = 1

Thus, these are not the slopes of perpendicular lines

<em><u>Option 2</u></em>

\frac{3}{4}\ and\ \frac{-4}{3}\\\\Product = \frac{3}{4} \times \frac{-4}{3}\\\\Product = -1

This option satisfies the slopes of perpendicular lines

<em><u>Option 3</u></em>

\frac{-2}{5}\ and\ \frac{-5}{2}\\\\Product = \frac{-2}{5} \times \frac{-5}{2} = 1

Thus, these are not the slopes of perpendicular lines

<em><u>Option 4</u></em>

2 and 2

Product = 2 x 2 = 4

Thus, these are not the slopes of perpendicular lines

7 0
3 years ago
A local country club has a membership of 600 and operates facilities that include an 18-hole championship golf course and 12 ten
shusha [124]

Answer:

0.45 = 45% probability that the member uses the golf course but not the tennis courts

Step-by-step explanation:

I am going to solve this question using the events as Venn sets.

I am going to say that:

Event A: Uses the golf courses.

Event B: Uses the tennis courts.

5% use neither of these facilities.

This means that P(A \cup B) = 1 - 0.05 = 0.95

75% use the golf course, 50% use the tennis courts

This means, respectively, by:

P(A) = 0.75, P(B) = 0.5

Probability that a member uses both:

This is P(A \cap B). We have that:

P(A \cap B) = P(A) + P(B) - P(A \cup B)

So

P(A \cap B) = 0.75 + 0.5 - 0.95 = 0.3

What is the probability that the member uses the golf course but not the tennis courts?

This is P(A - B), which is given by:

P(A - B) = P(A) - P(A \cap B)

So

P(A - B) = 0.75 - 0.3 = 0.45

0.45 = 45% probability that the member uses the golf course but not the tennis courts

3 0
3 years ago
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