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svetoff [14.1K]
3 years ago
13

Which of the following quotients are negative? Check all that apply. 1: 2.2 ÷ 9.5 2:–0.5 ÷ 0.021 3: –1.3 ÷ –54.321 0.4 ÷ –0.4 4:

Mathematics
2 answers:
pogonyaev3 years ago
8 0

Answer:

–0.5 ÷ 0.021 and 0.4 ÷ –0.4

Step-by-step explanation:

just did it

german3 years ago
3 0
We can already tell if a quotient is negative if the divisor or the dividend is a negative number. (Only 1 negative number and 1 positive number, because if there are two negative numbers then the outcome will be a positive.)

Question 4 has one negative number in it so it's already visible that the quotient is already negative. And if we did divide it the answer will be -1.

Question 3 has two negative numbers so we know that the outcome is a positive number. If solve the quotient is 0.023931813 which is clearly not a negative number.

Question 2 has one negative number so the answer will be negative. The quotient will be -23.80952381, which is clearly a negative number.

Question 1 doesn't have any negative numbers so the outcome will also be a positive number. The quotient for question 1 is 0.231578947.

So questions 2 and 4 both have negative quotients. While, questions 1 and 3 have positive quotients.
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PLS HELP MEEEI NEED ANSWERS ASAP ASAP
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Answer:

Associative.

Step-by-step explanation:

In addition and multiplication, it does not matter which two numbers you put together first. On the left aide 6 is associated with 3. On the right side 3 is grouped with 7.  It doesn't matter where 3 goes. You still get the same answer.

(6 + 3) + 7 = 6 + (3 + 7)

   9    +  7   =  6  + 10

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6 0
3 years ago
Could u help me make sure its the right answer i can't get this wrong .
Black_prince [1.1K]

Answer:

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5 0
3 years ago
Read 2 more answers
Answer correct you get brainliest answer​
zloy xaker [14]

Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

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The answer is 25
6 0
2 years ago
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