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2 years ago

Answer this please.

Mathematics

1 answer:

seropon [69]2 years ago

7 0

Answer:

3 ???

Step-by-step explanation:

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HELP PLS I WILL MARK BRAINLIEST, DUE TODAYY 100 POINTS!!!!!!!!!

Flauer [41]

Answer:

Y1 intercept = 2

(0,2) (3,-7)

m= (-7 - 2) / (3-0) =-9/3 = - 3

Then y = - 3x + 2

Y2 intercept = - 8

(0,-8) (3,-7)

m = (-7 - - 8) / (3-0) = 1/3

Then y= (1/3)x-8

5 0

2 years ago

Rectangle, Square, or Rhombus?

saveliy_v [14]

Answer:

maybe rhombus

Step-by-step explanation:

don't take my word for it

4 0

2 years ago

Read 2 more answers

The debate team has m members. Each member sold 5 coupon books as a fundraiser. Write an expression that shows the number of cou

Igoryamba

The equation should be:
m x 5 = 5m

5 0

2 years ago

Help I will be marking brainliest!!!

Andrews [41]

The answer is b

work is attached as a pic, in future draw a diagram, it’ll help u understand

3 0

3 years ago

What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12

Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, 2 is our minimum and 17 is our maximum.

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

$\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5$

The median is 12.5.

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

$\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6$

The first quartile is 6.

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

$\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15$

The third quartile is 15.

3 0

2 years ago