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sergeinik [125]
3 years ago
8

Question 5

Mathematics
1 answer:
nadezda [96]3 years ago
4 0
When you distribute you should get
12 {x}^{2}  + 8x - 3x - 2
Simplify to get
12 {x}^{2}  + 5x - 2
Answer 2 is correct
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The multiplication of two or more quantities may be expressed as the ? of the same quantities.
Mkey [24]

Answer:

PRODUCT

Step-by-step explanation:

? = Product because idk, common knowledge. I don't know how to explain it , it is just that I KNOW it.

3 0
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Proportion Problem. Each year Delta Dental does a survey of parents concerning the tradition of the Tooth Fairy. A random sample
cupoosta [38]

Answer:

Step-by-step explanation:

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3 years ago
13 POOINNTSSS PLEASE HELP ON 6-10 AND 13 TIMED TYSM IF U ANSWER
Leona [35]

Answer:

The answer is 12.8.

Step-by-step explanation:

0.16 times 80 = 12.8

8 0
3 years ago
Hannah went to the fair with her friends. She spent $7 to enter the fair and decided to play games until she won a stuffed anima
Evgesh-ka [11]

Answer:

24 games

Step-by-step explanation:

7 to enter

0.5 per game

19 dollars spent

19 = 7 + 0.5x

19 - 7 = 0.5x

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x = 12/0.5

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5 0
3 years ago
The number of potholes in any given 1 mile stretch of freeway pavement in Pennsylvania has a bell-shaped distribution. This dist
alexira [117]
<h3>Answer:   83.85%</h3>

This value is approximate.

==========================================================

Explanation:

Let's compute the z score for x = 40

z = (x-mu)/sigma

z = (40-47)/7

z = -1

We're exactly one standard deviation below the mean.

Repeat these steps for x = 68

z = (x-mu)/sigma

z = (68-47)/7

z = 3

This score is exactly three standard deviations above the mean.

Now refer to the Empirical Rule chart below. We'll add up the percentages that are between z = -1 and z = 3. This consists of the two pink regions (each 34%), the right blue region (13.5%) and the right green region (2.35%). These percentages are approximate.

34+34+13.5+2.35 = 83.85

<u>Roughly 83.85%</u> of the one-mile roadways have between 40 and 68 potholes.

5 0
2 years ago
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