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Nataly [62]
3 years ago
15

Mia lives in a neighborhood that has many pets. The mean number of pets in the neighborhood is 7. House one has four pets, house

two jas 12. Mia is house three, how many pets does misa have
Mathematics
1 answer:
Nataliya [291]3 years ago
3 0

Answer:

Mia has 5 pets

Step-by-step explanation:

Mean of pets=7

house 1 (4pets),house 2 (12 pets)

12 +4 +5=21

21÷3=7

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Can somebody help and explain this plzz
8_murik_8 [283]
A) Every T is worth 7 points, and every F is worth 3 points.  So if we let T = 7 and F = 3, we can count how many T's and F's each team scored and write it as an expression.


So for the East Side Bulldogs, they have 7 touchdowns and 6 field goals, thus the expression for them is:

7T + 6F

For the West Side Bulldogs, they have 5 touchdowns and 5 field goals, thus the expression for them is:

5T + 5F

B) The difference would be written as:
7T + 6F - (5T + 5F) = 2T + F

C) To determine how many more points the winning team has than the losing team, calculate the scores of the two teams.  Then subtract the smaller number from the larger number to determine the score differential.
8 0
4 years ago
What is f(4y)?? with f(x)=-2x-3
Olin [163]

Good evening ,

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Answer:

f(4y) = -8y - 3.

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Step-by-step explanation:

f(x) = -2x-3 Then f(4y) = -2(4y) -3 = -8y - 3.

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7 0
3 years ago
If D = Z + 6 and C = -2 + Z - Z^2, find an expression that equals 3D + C in standard form
kykrilka [37]

Answer:

4Z+16-Z²

Step-by-step explanation:

Given that,

D = Z+6

C = -2 + Z - Z²

We need to find the value of 3D+C.

So,

3D+C = 3(Z + 6)+(-2 + Z - Z²)

= 3Z+18-2+Z-Z²

= 4Z+16-Z²

So, the required expression is 4Z+16-Z².

6 0
3 years ago
A trucking firm has a large inventory of spare parts that have been in storage for a long time. It knowsthat some proportion of
Debora [2.8K]

Answer:

0.1546\leq \widehat{p}\leq 0.3513

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{19}{75}

\widehat{p}=0.253

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}

=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}

Confidence interval =0.1546\leq \widehat{p}\leq 0.3513

7 0
4 years ago
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