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Alenkasestr [34]
3 years ago
9

Help me with this problem

Mathematics
2 answers:
dybincka [34]3 years ago
6 0
It is -5/12.
Here's why...
To solve for n, you have to get n by itself. To get n by itself, you have to subtract 3/4 from 1/3 (as shown below). When you do that. You should get -5/12.
\frac{1}{3} -  \frac{3}{4} =  -\frac{5}{12}
Bumek [7]3 years ago
4 0
-5/12 would be your answer to the following equation. Hope this helps :)
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5n+8=43 solve please
svet-max [94.6K]
5n+8=43

43-8  =  35

35/5   =   7

n=7

4 0
3 years ago
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A rectangular room is 1.6 times as long as it is wide, and its perimeter is 34 meters. Find the dimensions of the room.​
Papessa [141]

Answer:

Step-by-step explanation:

x=1.6w and 2w+2x=34.

Simply substitute for x in the perimeter equation, and solve for w. Now compute x.

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A manager wants to determine if an employee training program has increased her employees’ customer satisfaction ratings. She ran
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A

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3 years ago
6 remainder 1 as a fraction
natka813 [3]
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6 0
3 years ago
Find the equation of a straight line passing throught the point listed and having the given gradient. Express your answer in the
Igoryamba
First let's try to find the equation in this form : <span>y = mx + c 

The gradient is given 3 . In a line's equation, x's coefficient represents the line's gradient.

So equation of a line with the gradient of 3, would look like this ;

</span>y= 3x + c
<span>
Now a point that the line passes through is given, (1, 2) 

This point's x-coordinate is 1 and y-coordinate is 2.

So we'll plug its x-coordinate value in the equation and also y-coordinate value. So we can solve it.

As you know, </span>x=1 and y=2

y = 3x + c

2\quad =\quad 3\cdot 1+c\\ \\ 2\quad =\quad 3+c\\ \\ 2-3\quad =\quad c\\ \\ -1\quad =\quad c

We found c = -1 

Also in a line's equation, c is constant and it represents the line's y-intercept

So let's build the line's equation.

m=3 and c=-1

y= mx + c

y= 3x -1

We found the line's equation in this form, y= mx + c

Now let's turn it into this form, ax + by + c = 0

y\quad =\quad 3x-1\\ \\ y-3x\quad =\quad -1\\ \\ y-3x+1\quad =\quad 0\\ \\ -3x+y+1\quad =\quad 0

Final answers,

\boxed { y\quad =\quad 3x-1 }

and 

\boxed { -3x+y+1\quad =\quad 0 }

I hope this was clear enough :)




<span>


</span>
5 0
4 years ago
Read 2 more answers
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