Answer:
Part 1) The x-intercept is the point (-6,0)
Part 2) The y-intercept is the point (0,2)
Step-by-step explanation:
we know that
The x-intercept is the value of x when the value of y is equal to zero
The y-intercept is the value of y when the value of x is equal to zero
we have

Part 1) Find the x-intercept
For y=0
substitute the value of y in the linear equation and solve for x



The x-intercept is the point (-6,0)
Part 2) Find the y-intercept
For x=0
substitute the value of x in the linear equation and solve for y



The y-intercept is the point (0,2)
1) either you'll get a negative number
Or
2) You'll get a positive Number..
But I'm guess you'll get a positive number
Answer: The width is: " 10 in. " .
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Explanation:
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Consider a "rectangular prism".
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The formula for the Volume of a rectangular prism:
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V = L * w * h ;
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in which:
V = volume = 120 in.³ ;
L = length = 8 in.
w = width = ??
h = height = 1.5 in.
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We want to solve for "w" (width) ;
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Given the formula:
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V = L * w * h ;
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Rewrite the formula; by dividing EACH SIDE of the equation by
"(L * h)" ; to isolate "w" on one side of the equation;
and to solve for "w" ;
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→ V / (L * h) = ( L * w * h) / (L * h) ;
to get:
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→ V / (L * h) = w ;
↔ w = V / (L * h) ;
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Plug in our given values for "V", "L"; and "h"; to solve for "w" ;
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→ w = (120 in.³) / (8 in. * 1.5 in.) ;
→ w = (120 in.³) / (12 in.²) ;
→ w = (120/12) in. = 10 in.
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Y = -7x + 2
y = 9x - 14
-7x + 2 = 9x - 14
14 + 2 = 9x + 7x
16 = 16x
1 = x
y = -7x + 2
y = -7(1) + 2
y = -7 + 2
y = -5
solution is : (1,-5) <==
Answer:
Step-by-step explanation:
My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.