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kvv77 [185]
2 years ago
10

¿Cuál es el peso total en kilos de los dulces?A23Boln​

Mathematics
1 answer:
Doss [256]2 years ago
4 0

pesan 3kilos.

3/1=0.3kilos

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Number 5 please I beg.
gavmur [86]

Answer:

X = 25

Step-by-step explanation:

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3 years ago
Find the value of 42 6 ÷ 2.71119
Leno4ka [110]
 if i guess and do it the answer ten times is this 157.128314
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3 years ago
Which of these cannot represent the lengths of the sides of a right triangle?
Sholpan [36]
<h3>Answer: Choice D. 8m, 9m, 10m</h3>

==================================

Explanation:

If a = 8 and b = 9 are the two legs of a triangle and c = 10 is the hypotenuse, then

a^2 + b^2 = c^2

8^2 + 9^2 = 10^2

64 + 81 = 100

145 = 100

We get a false equation as 145 and 100 are two different values. So the original equation is false when (a,b,c) = (8,9,10)

By the converse of the pythagorean theorem, we have proven that this particular triangle is not a right triangle

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Contrast this with something like choice A where we have a = 3, b = 4, c = 5 leading to

a^2 + b^2 = c^2

3^2 + 4^2 = 5^2

9 + 16 = 25

25 = 25

we get a true equation so a triangle with sides 3,4,5 is a right triangle. Choices B and C follow a similar path.

4 0
3 years ago
Read 2 more answers
In the football game between NM and JL. It's the end of the second half and the cougars are attempting a miraculous 50 yard fiel
Yanka [14]

Answer:

88.02 ft/s

Step-by-step explanation:

Angle with the horizontal, θ =25°

Initial velocity, v = 60 mph

1 mph = 1.467 ft/s

60 mph = 60 × 1.467 ft/s = 88.02 ft/s

Vertical component, v sin θ = 88.02 sin 25° = 37.2 ft/s

Horizontal component, v cos θ = 88.02 cos 25°= 79.8 ft/s

3 0
3 years ago
Hey, Its the same person. This is Algebra 2. Please Help!
suter [353]

Answer:

first option

Step-by-step explanation:

Given

f(x) = \frac{2x^2+5x-12}{x+4} ← factorise the numerator

     = \frac{(x + 4)(2x-3)}{x+4} ← cancel (x + 4) on numerator/ denominator

     = 2x - 3

Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is

x = - 4

Substitute x = - 4 into the simplified f(x) for y- coordinate

f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11

The discontinuity occurs at (- 4, - 11 )

To obtain the zero let f(x) = 0, that is

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

There is a zero at ( \frac{3}{2}, 0 )

Thus

discontinuity at (- 4, - 11 ), zero at ( \frac{3}{2}, 0 )

7 0
3 years ago
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