Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
0.235 = 235/1000= 47/200
Answer: 47/200
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Answer:
a) the common difference is 20
b)
c) the common difference is -13
d)
Step-by-step explanation:
a) what is the common difference of the sequence xn
Looking at the table, we get x_3=16, x_4=36 and x_5= 56
Deterring the common difference by subtracting x_4 from x_3 we get
36-16 =20
So, the common difference is 20
b) what is x_8? what is x_12
The formula used is:
We know common difference d= 20, we need to find
Using we can find
So, We have
Now finding
So,
Now finding
So,
c) what is the common difference of the sequence
Looking at the table, we get a_7=104, a_8=91 and a_9= 78
Deterring the common difference by subtracting a_7 from a_8 we get
91-104 =-13
So, the common difference is -13
d) what is a_12? what is a_15?
The formula used is:
We know common difference d= -13, we need to find
Using we can find
So, We have
Now finding , put n=12
So,
Now finding , put n=15
So,
Answer:
R = (-12, 22)
Step-by-step explanation:
Unfortunately it's not a straight line, so gonna need to put in some extra work. Basically think of it like breaking it into it's horizontal and vertical components then doubling them.
From Q to M you move 10 spaces to the left, so to go from M to R you will go another 10 to the left. Similarly, you start at -10 for the y value and go up 16 to 6, and you will need to go up another 16 to get to R.
So for x, 8 -10 = -2 then -2 - 10 = -12, so R's x value is -12
y we do the same thing. Gonna do it in one step though. -10 + 16 + 16 = 22
So R is (-12, 22)
Answer:
3 hrs 4.6 mins
Step-by-step explanation:
1/5 + 1/8 = 1/x
x = 40/13