The answer would be 3.341
Answer:
30 I N
Step-by-step explanation:
Answer:
<h2>The function f(x) = (x - 6)(x - 6) has only one x-intercept. But at (6, 0) not at (-6, 0).</h2>
Step-by-step explanation:
The intercept form of a quadratic equation (parabola):

p, q - x-intercepts
Therefore
The function f(x) = x(x - 6) = (x - 0)(x - 6) has two x-intercepts at (0, 0) and (6, 0)
The function f(x) = (x - 6)(x - 6) has only one x-intercept at (6, 0)
The function f(x) = (x + 6)(x - 6) = (x - (-6))(x - 6)
has two x-intercept at (-6, 0) and (6, 0)
The function f(x) = (x + 1)(x + 6) = (x - (-1))(x - (-6))
has two x-intercepts at (-1, 0) and (-6, 0).
Step-by-step explanation:
question number 2 first part X + 2 is equal to 7 .. x is equal to 7 - 2x is equal to 5 ..second part 3 x minus 1 is equal to 3 x is equal to 23 - 1 = 3x=24 x=24÷3=x=8ans