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3 years ago

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Benny grew 5 watermelons. Joan grew 2 watermelons. How manywatermelons did they grow in all ?

2 answers:

stiks02 [169]3 years ago

4 0

Answer: it's 7

Step-by-step explanation:

You just add the numbers together like, 5+2 and then you get 7

Alenkinab [10]3 years ago

3 0

Answer:Benny and Joan grew 7 watermelons Total

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Which of the following equations best describes a square root function that is reflected across the x-axis and has a vertex of (

Minchanka [31]

Answer:

C

Step-by-step explanation:

Rather than picking, let's try to construct one from the description.

reflected over the x axis means - $\sqrt{x}$

the vertex is usually at (0,0), now how do we move a graph? or in other words translating it.

To move left and right you use $\sqrt{x-h}$ where if you subtract h you move right and if you add h you move left. we go from (0,0) to (-4,2). so 0 to -4 is 4 left, so that means we add 4.

To move up and down we use $\sqrt{x}+v$ Here if v is positive you move up and if v is negative you move down. going from (0,0) to (-4,2) it moves up 2

So now we put them all together $-\sqrt{x+4}+2$ And if you look, C matches that exactly.

6 0

3 years ago

Let f(w) = 2w^3 - 5. What is f(4)?

ZanzabumX [31]

F(4) = 2(4)^3 -5
= 2(64) -5

= 128-5
= 123

Hope this helps!

3 0

3 years ago

Read 2 more answers

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

3 years ago

An education researcher randomly selected 48 middle schools from across the country and interviews every teacher of the selected

swat32

Answer:

graphs

Step-by-step explanation:

the answer is graph

it can be any graphs (pie chart, bar graph)

the question doesn't say about the data collected

8 0

3 years ago

Find the arc length of the semicircle. Either enter an exact answer in terms of π or use 3.14 for π and enter your answer as a d

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

The formula for the length of an arc is s = rФ.

Thus, the arc length of a semicircle is S = rФ/2.

Here the radius is 5 (half the diameter), and so in this case the arc length is

S = (5 units)π/2, or S = (5/2)(3.14) units, or approximately S = 7.85 units

6 0

3 years ago